examples/jssp.mod
author Alpar Juttner <alpar@cs.elte.hu>
Mon, 06 Dec 2010 13:09:21 +0100
changeset 1 c445c931472f
permissions -rw-r--r--
Import glpk-4.45

- Generated files and doc/notes are removed
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/* JSSP, Job-Shop Scheduling Problem */
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/* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */
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/* The Job-Shop Scheduling Problem (JSSP) is to schedule a set of jobs
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   on a set of machines, subject to the constraint that each machine can
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   handle at most one job at a time and the fact that each job has a
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   specified processing order through the machines. The objective is to
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   schedule the jobs so as to minimize the maximum of their completion
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   times.
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   Reference:
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   D. Applegate and W. Cook, "A Computational Study of the Job-Shop
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   Scheduling Problem", ORSA J. On Comput., Vol. 3, No. 2, Spring 1991,
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   pp. 149-156. */
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param n, integer, > 0;
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/* number of jobs */
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param m, integer, > 0;
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/* number of machines */
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set J := 1..n;
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/* set of jobs */
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set M := 1..m;
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/* set of machines */
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param sigma{j in J, t in 1..m}, in M;
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/* permutation of the machines, which represents the processing order
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   of j through the machines: j must be processed first on sigma[j,1],
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   then on sigma[j,2], etc. */
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check{j in J, t1 in 1..m, t2 in 1..m: t1 <> t2}:
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      sigma[j,t1] != sigma[j,t2];
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/* sigma must be permutation */
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param p{j in J, a in M}, >= 0;
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/* processing time of j on a */
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var x{j in J, a in M}, >= 0;
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/* starting time of j on a */
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s.t. ord{j in J, t in 2..m}:
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      x[j, sigma[j,t]] >= x[j, sigma[j,t-1]] + p[j, sigma[j,t-1]];
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/* j can be processed on sigma[j,t] only after it has been completely
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   processed on sigma[j,t-1] */
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/* The disjunctive condition that each machine can handle at most one
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   job at a time is the following:
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      x[i,a] >= x[j,a] + p[j,a]  or  x[j,a] >= x[i,a] + p[i,a]
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   for all i, j in J, a in M. This condition is modeled through binary
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   variables Y as shown below. */
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var Y{i in J, j in J, a in M}, binary;
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/* Y[i,j,a] is 1 if i scheduled before j on machine a, and 0 if j is
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   scheduled before i */
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param K := sum{j in J, a in M} p[j,a];
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/* some large constant */
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display K;
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s.t. phi{i in J, j in J, a in M: i <> j}:
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      x[i,a] >= x[j,a] + p[j,a] - K * Y[i,j,a];
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/* x[i,a] >= x[j,a] + p[j,a] iff Y[i,j,a] is 0 */
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s.t. psi{i in J, j in J, a in M: i <> j}:
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      x[j,a] >= x[i,a] + p[i,a] - K * (1 - Y[i,j,a]);
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/* x[j,a] >= x[i,a] + p[i,a] iff Y[i,j,a] is 1 */
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var z;
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/* so-called makespan */
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s.t. fin{j in J}: z >= x[j, sigma[j,m]] + p[j, sigma[j,m]];
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/* which is the maximum of the completion times of all the jobs */
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minimize obj: z;
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/* the objective is to make z as small as possible */
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data;
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/* These data correspond to the instance ft06 (mt06) from:
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   H. Fisher, G.L. Thompson (1963), Probabilistic learning combinations
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   of local job-shop scheduling rules, J.F. Muth, G.L. Thompson (eds.),
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   Industrial Scheduling, Prentice Hall, Englewood Cliffs, New Jersey,
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   225-251 */
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/* The optimal solution is 55 */
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param n := 6;
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param m := 6;
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param sigma :  1  2  3  4  5  6 :=
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          1    3  1  2  4  6  5
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          2    2  3  5  6  1  4
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          3    3  4  6  1  2  5
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          4    2  1  3  4  5  6
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          5    3  2  5  6  1  4
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          6    2  4  6  1  5  3 ;
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param p     :  1  2  3  4  5  6 :=
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          1    3  6  1  7  6  3
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          2   10  8  5  4 10 10
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          3    9  1  5  4  7  8
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          4    5  5  5  3  8  9
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          5    3  3  9  1  5  4
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          6   10  3  1  3  4  9 ;
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end;