alpar@1
|
1 |
/* ZEBRA, Who Owns the Zebra? */
|
alpar@1
|
2 |
|
alpar@1
|
3 |
/* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */
|
alpar@1
|
4 |
|
alpar@1
|
5 |
########################################################################
|
alpar@1
|
6 |
# The Zebra Puzzle is a well-known logic puzzle.
|
alpar@1
|
7 |
#
|
alpar@1
|
8 |
# It is often called "Einstein's Puzzle" or "Einstein's Riddle"
|
alpar@1
|
9 |
# because it is said to have been invented by Albert Einstein as a boy,
|
alpar@1
|
10 |
# with the common claim that Einstein said "only 2 percent of the
|
alpar@1
|
11 |
# world's population can solve". It is also sometimes attributed to
|
alpar@1
|
12 |
# Lewis Carroll. However, there is no known evidence for Einstein's or
|
alpar@1
|
13 |
# Carroll's authorship.
|
alpar@1
|
14 |
#
|
alpar@1
|
15 |
# There are several versions of this puzzle. The version below is
|
alpar@1
|
16 |
# quoted from the first known publication in Life International
|
alpar@1
|
17 |
# magazine on December 17, 1962.
|
alpar@1
|
18 |
#
|
alpar@1
|
19 |
# 1. There are five houses.
|
alpar@1
|
20 |
# 2. The Englishman lives in the red house.
|
alpar@1
|
21 |
# 3. The Spaniard owns the dog.
|
alpar@1
|
22 |
# 4. Coffee is drunk in the green house.
|
alpar@1
|
23 |
# 5. The Ukrainian drinks tea.
|
alpar@1
|
24 |
# 6. The green house is immediately to the right of the ivory house.
|
alpar@1
|
25 |
# 7. The Old Gold smoker owns snails.
|
alpar@1
|
26 |
# 8. Kools are smoked in the yellow house.
|
alpar@1
|
27 |
# 9. Milk is drunk in the middle house.
|
alpar@1
|
28 |
# 10. The Norwegian lives in the first house.
|
alpar@1
|
29 |
# 11. The man who smokes Chesterfields lives in the house next to the
|
alpar@1
|
30 |
# man with the fox.
|
alpar@1
|
31 |
# 12. Kools are smoked in the house next to the house where the horse
|
alpar@1
|
32 |
# is kept.
|
alpar@1
|
33 |
# 13. The Lucky Strike smoker drinks orange juice.
|
alpar@1
|
34 |
# 14. The Japanese smokes Parliaments.
|
alpar@1
|
35 |
# 15. The Norwegian lives next to the blue house.
|
alpar@1
|
36 |
#
|
alpar@1
|
37 |
# Now, who drinks water? Who owns the zebra?
|
alpar@1
|
38 |
#
|
alpar@1
|
39 |
# In the interest of clarity, it must be added that each of the five
|
alpar@1
|
40 |
# houses is painted a different color, and their inhabitants are of
|
alpar@1
|
41 |
# different national extractions, own different pets, drink different
|
alpar@1
|
42 |
# beverages and smoke different brands of American cigarettes. One
|
alpar@1
|
43 |
# other thing: In statement 6, right means your right.
|
alpar@1
|
44 |
#
|
alpar@1
|
45 |
# (From Wikipedia, the free encyclopedia.)
|
alpar@1
|
46 |
########################################################################
|
alpar@1
|
47 |
|
alpar@1
|
48 |
set HOUSE := { 1..5 };
|
alpar@1
|
49 |
|
alpar@1
|
50 |
set COLOR := { "blue", "green", "ivory", "red", "yellow" };
|
alpar@1
|
51 |
|
alpar@1
|
52 |
set NATIONALITY := { "Englishman", "Japanese", "Norwegian", "Spaniard",
|
alpar@1
|
53 |
"Ukranian" };
|
alpar@1
|
54 |
|
alpar@1
|
55 |
set DRINK := { "coffee", "milk", "orange_juice", "tea", "water" };
|
alpar@1
|
56 |
|
alpar@1
|
57 |
set SMOKE := { "Chesterfield", "Kools", "Lucky_Strike", "Old_Gold",
|
alpar@1
|
58 |
"Parliament" };
|
alpar@1
|
59 |
|
alpar@1
|
60 |
set PET := { "dog", "fox", "horse", "snails", "zebra" };
|
alpar@1
|
61 |
|
alpar@1
|
62 |
var color{HOUSE, COLOR}, binary;
|
alpar@1
|
63 |
c1{h in HOUSE}: sum{c in COLOR} color[h,c] = 1;
|
alpar@1
|
64 |
c2{c in COLOR}: sum{h in HOUSE} color[h,c] = 1;
|
alpar@1
|
65 |
|
alpar@1
|
66 |
var nationality{HOUSE, NATIONALITY}, binary;
|
alpar@1
|
67 |
n1{h in HOUSE}: sum{n in NATIONALITY} nationality[h,n] = 1;
|
alpar@1
|
68 |
n2{n in NATIONALITY}: sum{h in HOUSE} nationality[h,n] = 1;
|
alpar@1
|
69 |
|
alpar@1
|
70 |
var drink{HOUSE, DRINK}, binary;
|
alpar@1
|
71 |
d1{h in HOUSE}: sum{d in DRINK} drink[h,d] = 1;
|
alpar@1
|
72 |
d2{d in DRINK}: sum{h in HOUSE} drink[h,d] = 1;
|
alpar@1
|
73 |
|
alpar@1
|
74 |
var smoke{HOUSE, SMOKE}, binary;
|
alpar@1
|
75 |
s1{h in HOUSE}: sum{s in SMOKE} smoke[h,s] = 1;
|
alpar@1
|
76 |
s2{s in SMOKE}: sum{h in HOUSE} smoke[h,s] = 1;
|
alpar@1
|
77 |
|
alpar@1
|
78 |
var pet{HOUSE, PET}, binary;
|
alpar@1
|
79 |
p1{h in HOUSE}: sum{p in PET} pet[h,p] = 1;
|
alpar@1
|
80 |
p2{p in PET}: sum{h in HOUSE} pet[h,p] = 1;
|
alpar@1
|
81 |
|
alpar@1
|
82 |
/* the Englishman lives in the red house */
|
alpar@1
|
83 |
f2{h in HOUSE}: nationality[h,"Englishman"] = color[h,"red"];
|
alpar@1
|
84 |
|
alpar@1
|
85 |
/* the Spaniard owns the dog */
|
alpar@1
|
86 |
f3{h in HOUSE}: nationality[h,"Spaniard"] = pet[h,"dog"];
|
alpar@1
|
87 |
|
alpar@1
|
88 |
/* coffee is drunk in the green house */
|
alpar@1
|
89 |
f4{h in HOUSE}: drink[h,"coffee"] = color[h,"green"];
|
alpar@1
|
90 |
|
alpar@1
|
91 |
/* the Ukrainian drinks tea */
|
alpar@1
|
92 |
f5{h in HOUSE}: nationality[h,"Ukranian"] = drink[h,"tea"];
|
alpar@1
|
93 |
|
alpar@1
|
94 |
/* the green house is immediately to the right of the ivory house */
|
alpar@1
|
95 |
f6{h in HOUSE}:
|
alpar@1
|
96 |
color[h,"green"] = if h = 1 then 0 else color[h-1,"ivory"];
|
alpar@1
|
97 |
|
alpar@1
|
98 |
/* the Old Gold smoker owns snails */
|
alpar@1
|
99 |
f7{h in HOUSE}: smoke[h,"Old_Gold"] = pet[h,"snails"];
|
alpar@1
|
100 |
|
alpar@1
|
101 |
/* Kools are smoked in the yellow house */
|
alpar@1
|
102 |
f8{h in HOUSE}: smoke[h,"Kools"] = color[h,"yellow"];
|
alpar@1
|
103 |
|
alpar@1
|
104 |
/* milk is drunk in the middle house */
|
alpar@1
|
105 |
f9: drink[3,"milk"] = 1;
|
alpar@1
|
106 |
|
alpar@1
|
107 |
/* the Norwegian lives in the first house */
|
alpar@1
|
108 |
f10: nationality[1,"Norwegian"] = 1;
|
alpar@1
|
109 |
|
alpar@1
|
110 |
/* the man who smokes Chesterfields lives in the house next to the man
|
alpar@1
|
111 |
with the fox */
|
alpar@1
|
112 |
f11{h in HOUSE}:
|
alpar@1
|
113 |
(1 - smoke[h,"Chesterfield"]) +
|
alpar@1
|
114 |
(if h = 1 then 0 else pet[h-1,"fox"]) +
|
alpar@1
|
115 |
(if h = 5 then 0 else pet[h+1,"fox"]) >= 1;
|
alpar@1
|
116 |
|
alpar@1
|
117 |
/* Kools are smoked in the house next to the house where the horse is
|
alpar@1
|
118 |
kept */
|
alpar@1
|
119 |
f12{h in HOUSE}:
|
alpar@1
|
120 |
(1 - smoke[h,"Kools"]) +
|
alpar@1
|
121 |
(if h = 1 then 0 else pet[h-1,"horse"]) +
|
alpar@1
|
122 |
(if h = 5 then 0 else pet[h+1,"horse"]) >= 1;
|
alpar@1
|
123 |
|
alpar@1
|
124 |
/* the Lucky Strike smoker drinks orange juice */
|
alpar@1
|
125 |
f13{h in HOUSE}: smoke[h,"Lucky_Strike"] = drink[h,"orange_juice"];
|
alpar@1
|
126 |
|
alpar@1
|
127 |
/* the Japanese smokes Parliaments */
|
alpar@1
|
128 |
f14{h in HOUSE}: nationality[h,"Japanese"] = smoke[h,"Parliament"];
|
alpar@1
|
129 |
|
alpar@1
|
130 |
/* the Norwegian lives next to the blue house */
|
alpar@1
|
131 |
f15{h in HOUSE}:
|
alpar@1
|
132 |
(1 - nationality[h,"Norwegian"]) +
|
alpar@1
|
133 |
(if h = 1 then 0 else color[h-1,"blue"]) +
|
alpar@1
|
134 |
(if h = 5 then 0 else color[h+1,"blue"]) >= 1;
|
alpar@1
|
135 |
|
alpar@1
|
136 |
solve;
|
alpar@1
|
137 |
|
alpar@1
|
138 |
printf "\n";
|
alpar@1
|
139 |
printf "HOUSE COLOR NATIONALITY DRINK SMOKE PET\n";
|
alpar@1
|
140 |
for {h in HOUSE}
|
alpar@1
|
141 |
{ printf "%5d", h;
|
alpar@1
|
142 |
printf{c in COLOR: color[h,c]} " %-6s", c;
|
alpar@1
|
143 |
printf{n in NATIONALITY: nationality[h,n]} " %-11s", n;
|
alpar@1
|
144 |
printf{d in DRINK: drink[h,d]} " %-12s", d;
|
alpar@1
|
145 |
printf{s in SMOKE: smoke[h,s]} " %-12s", s;
|
alpar@1
|
146 |
printf{p in PET: pet[h,p]} " %-6s", p;
|
alpar@1
|
147 |
printf "\n";
|
alpar@1
|
148 |
}
|
alpar@1
|
149 |
printf "\n";
|
alpar@1
|
150 |
|
alpar@1
|
151 |
end;
|