examples/color.mod
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     1 /* COLOR, Graph Coloring Problem */
       
     2 
       
     3 /* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */
       
     4 
       
     5 /* Given an undirected loopless graph G = (V, E), where V is a set of
       
     6    nodes, E <= V x V is a set of arcs, the Graph Coloring Problem is to
       
     7    find a mapping (coloring) F: V -> C, where C = {1, 2, ... } is a set
       
     8    of colors whose cardinality is as small as possible, such that
       
     9    F(i) != F(j) for every arc (i,j) in E, that is adjacent nodes must
       
    10    be assigned different colors. */
       
    11 
       
    12 param n, integer, >= 2;
       
    13 /* number of nodes */
       
    14 
       
    15 set V := {1..n};
       
    16 /* set of nodes */
       
    17 
       
    18 set E, within V cross V;
       
    19 /* set of arcs */
       
    20 
       
    21 check{(i,j) in E}: i != j;
       
    22 /* there must be no loops */
       
    23 
       
    24 /* We need to estimate an upper bound of the number of colors |C|.
       
    25    The number of nodes |V| can be used, however, for sparse graphs such
       
    26    bound is not very good. To obtain a more suitable estimation we use
       
    27    an easy "greedy" heuristic. Let nodes 1, ..., i-1 are already
       
    28    assigned some colors. To assign a color to node i we see if there is
       
    29    an existing color not used for coloring nodes adjacent to node i. If
       
    30    so, we use this color, otherwise we introduce a new color. */
       
    31 
       
    32 set EE := setof{(i,j) in E} (i,j) union setof{(i,j) in E} (j,i);
       
    33 /* symmetrisized set of arcs */
       
    34 
       
    35 param z{i in V, case in 0..1} :=
       
    36 /* z[i,0] = color index assigned to node i
       
    37    z[i,1] = maximal color index used for nodes 1, 2, ..., i-1 which are
       
    38             adjacent to node i */
       
    39 (  if case = 0 then
       
    40    (  /* compute z[i,0] */
       
    41       min{c in 1..z[i,1]}
       
    42       (  if not exists{j in V: j < i and (i,j) in EE} z[j,0] = c then
       
    43             c
       
    44          else
       
    45             z[i,1] + 1
       
    46       )
       
    47    )
       
    48    else
       
    49    (  /* compute z[i,1] */
       
    50       if not exists{j in V: j < i} (i,j) in EE then
       
    51          1
       
    52       else
       
    53          max{j in V: j < i and (i,j) in EE} z[j,0]
       
    54    )
       
    55 );
       
    56 
       
    57 check{(i,j) in E}: z[i,0] != z[j,0];
       
    58 /* check that all adjacent nodes are assigned distinct colors */
       
    59 
       
    60 param nc := max{i in V} z[i,0];
       
    61 /* number of colors used by the heuristic; obviously, it is an upper
       
    62    bound of the optimal solution */
       
    63 
       
    64 display nc;
       
    65 
       
    66 var x{i in V, c in 1..nc}, binary;
       
    67 /* x[i,c] = 1 means that node i is assigned color c */
       
    68 
       
    69 var u{c in 1..nc}, binary;
       
    70 /* u[c] = 1 means that color c is used, i.e. assigned to some node */
       
    71 
       
    72 s.t. map{i in V}: sum{c in 1..nc} x[i,c] = 1;
       
    73 /* each node must be assigned exactly one color */
       
    74 
       
    75 s.t. arc{(i,j) in E, c in 1..nc}: x[i,c] + x[j,c] <= u[c];
       
    76 /* adjacent nodes cannot be assigned the same color */
       
    77 
       
    78 minimize obj: sum{c in 1..nc} u[c];
       
    79 /* objective is to minimize the number of colors used */
       
    80 
       
    81 data;
       
    82 
       
    83 /* These data correspond to the instance myciel3.col from:
       
    84    http://mat.gsia.cmu.edu/COLOR/instances.html */
       
    85 
       
    86 /* The optimal solution is 4 */
       
    87 
       
    88 param n := 11;
       
    89 
       
    90 set E :=
       
    91  1 2
       
    92  1 4
       
    93  1 7
       
    94  1 9
       
    95  2 3
       
    96  2 6
       
    97  2 8
       
    98  3 5
       
    99  3 7
       
   100  3 10
       
   101  4 5
       
   102  4 6
       
   103  4 10
       
   104  5 8
       
   105  5 9
       
   106  6 11
       
   107  7 11
       
   108  8 11
       
   109  9 11
       
   110  10 11
       
   111 ;
       
   112 
       
   113 end;