examples/min01ks.mod
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     1 /* min01ks.mod - finding minimal equivalent 0-1 knapsack inequality */
       
     2 
       
     3 /* Written in GNU MathProg by Andrew Makhorin <mao@gnu.org> */
       
     4 
       
     5 /* It is obvious that for a given 0-1 knapsack inequality
       
     6 
       
     7       a[1] x[1] + ... + a[n] x[n] <= b,  x[j] in {0, 1}              (1)
       
     8 
       
     9    there exist infinitely many equivalent inequalities with exactly the
       
    10    same feasible solutions.
       
    11 
       
    12    Given a[j]'s and b this model allows to find an inequality
       
    13 
       
    14       alfa[1] x[1] + ... + alfa[n] x[n] <= beta,  x[j] in {0, 1},    (2)
       
    15 
       
    16    which is equivalent to (1) and where alfa[j]'s and beta are smallest
       
    17    non-negative integers.
       
    18 
       
    19    This model has the following formulation:
       
    20 
       
    21       minimize
       
    22 
       
    23          z = |alfa[1]| + ... + |alfa[n]| + |beta| =                  (3)
       
    24 
       
    25            = alfa[1] + ... + alfa[n] + beta
       
    26 
       
    27       subject to
       
    28 
       
    29          alfa[1] x[1] + ... + alfa[n] x[n] <= beta                   (4)
       
    30 
       
    31                               for all x satisfying to (1)
       
    32 
       
    33          alfa[1] x[1] + ... + alfa[n] x[n] >= beta + 1               (5)
       
    34 
       
    35                               for all x not satisfying to (1)
       
    36 
       
    37          alfa[1], ..., alfa[n], beta are non-negative integers.
       
    38 
       
    39    Note that this model has n+1 variables and 2^n constraints.
       
    40 
       
    41    It is interesting, as noticed in [1] and explained in [2], that
       
    42    in most cases LP relaxation of the MIP formulation above has integer
       
    43    optimal solution.
       
    44 
       
    45    References
       
    46 
       
    47    1. G.H.Bradley, P.L.Hammer, L.Wolsey, "Coefficient Reduction for
       
    48       Inequalities in 0-1 Variables", Math.Prog.7 (1974), 263-282.
       
    49 
       
    50    2. G.J.Koehler, "A Study on Coefficient Reduction of Binary Knapsack
       
    51       Inequalities", University of Florida, 2001. */
       
    52 
       
    53 param n, integer, > 0;
       
    54 /* number of variables in the knapsack inequality */
       
    55 
       
    56 set N := 1..n;
       
    57 /* set of knapsack items */
       
    58 
       
    59 /* all binary n-vectors are numbered by 0, 1, ..., 2^n-1, where vector
       
    60    0 is 00...00, vector 1 is 00...01, etc. */
       
    61 
       
    62 set U := 0..2^n-1;
       
    63 /* set of numbers of all binary n-vectors */
       
    64 
       
    65 param x{i in U, j in N}, binary, := (i div 2^(j-1)) mod 2;
       
    66 /* x[i,j] is j-th component of i-th binary n-vector */
       
    67 
       
    68 param a{j in N}, >= 0;
       
    69 /* original coefficients */
       
    70 
       
    71 param b, >= 0;
       
    72 /* original right-hand side */
       
    73 
       
    74 set D := setof{i in U: sum{j in N} a[j] * x[i,j] <= b} i;
       
    75 /* set of numbers of binary n-vectors, which (vectors) are feasible,
       
    76    i.e. satisfy to the original knapsack inequality (1) */
       
    77 
       
    78 var alfa{j in N}, integer, >= 0;
       
    79 /* coefficients to be found */
       
    80 
       
    81 var beta, integer, >= 0;
       
    82 /* right-hand side to be found */
       
    83 
       
    84 minimize z: sum{j in N} alfa[j] + beta; /* (3) */
       
    85 
       
    86 phi{i in D}: sum{j in N} alfa[j] * x[i,j] <= beta; /* (4) */
       
    87 
       
    88 psi{i in U diff D}: sum{j in N} alfa[j] * x[i,j] >= beta + 1; /* (5) */
       
    89 
       
    90 solve;
       
    91 
       
    92 printf "\nOriginal 0-1 knapsack inequality:\n";
       
    93 for {j in 1..n} printf (if j = 1 then "" else " + ") & "%g x%d",
       
    94    a[j], j;
       
    95 printf " <= %g\n", b;
       
    96 printf "\nMinimized equivalent inequality:\n";
       
    97 for {j in 1..n} printf (if j = 1 then "" else " + ") & "%g x%d",
       
    98    alfa[j], j;
       
    99 printf " <= %g\n\n", beta;
       
   100 
       
   101 data;
       
   102 
       
   103 /* These data correspond to the very first example from [1]. */
       
   104 
       
   105 param n := 8;
       
   106 
       
   107 param a := [1]65, [2]64, [3]41, [4]22, [5]13, [6]12, [7]8, [8]2;
       
   108 
       
   109 param b := 80;
       
   110 
       
   111 end;