diff -r d59bea55db9b -r c445c931472f examples/gap.mod --- /dev/null Thu Jan 01 00:00:00 1970 +0000 +++ b/examples/gap.mod Mon Dec 06 13:09:21 2010 +0100 @@ -0,0 +1,79 @@ +/* GAP, Generalized Assignment Problem */ + +/* Written in GNU MathProg by Andrew Makhorin */ + +/* The Generalized Assignment Problem (GAP) is to assign a set of jobs + to a set of agents subject to the constraints that each job must be + assigned exactly to one agent and the total resources consumed by all + jobs assigned to an agent must not exceed the agent's capacity. */ + +param m, integer, > 0; +/* number of agents */ + +param n, integer, > 0; +/* number of jobs */ + +set I := 1..m; +/* set of agents */ + +set J := 1..n; +/* set of jobs */ + +param a{i in I, j in J}, >= 0; +/* resource consumed in allocating job j to agent i */ + +param b{i in I}, >= 0; +/* resource capacity of agent i */ + +param c{i in I, j in J}, >= 0; +/* cost of allocating job j to agent i */ + +var x{i in I, j in J}, binary; +/* x[i,j] = 1 means job j is assigned to agent i */ + +s.t. one{j in J}: sum{i in I} x[i,j] = 1; +/* job j must be assigned exactly to one agent */ + +s.t. lim{i in I}: sum{j in J} a[i,j] * x[i,j] <= b[i]; +/* total amount of resources consumed by all jobs assigned to agent i + must not exceed the agent's capacity */ + +minimize obj: sum{i in I, j in J} c[i,j] * x[i,j]; +/* the objective is to find cheapest assignment (note that gap can also + be formulated as maximization problem) */ + +data; + +/* These data correspond to the instance c515-1 (gap1) from: + + I.H. Osman, "Heuristics for the Generalised Assignment Problem: + Simulated Annealing and Tabu Search Approaches", OR Spektrum, Volume + 17, 211-225, 1995 + + D. Cattrysse, M. Salomon and L.N. Van Wassenhove, "A set partitioning + heuristic for the generalized assignment problem", European Journal + of Operational Research, Volume 72, 167-174, 1994 */ + +/* The optimal solution is 261 (minimization) or 336 (maximization) */ + +param m := 5; + +param n := 15; + +param a : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 := + 1 8 15 14 23 8 16 8 25 9 17 25 15 10 8 24 + 2 15 7 23 22 11 11 12 10 17 16 7 16 10 18 22 + 3 21 20 6 22 24 10 24 9 21 14 11 14 11 19 16 + 4 20 11 8 14 9 5 6 19 19 7 6 6 13 9 18 + 5 8 13 13 13 10 20 25 16 16 17 10 10 5 12 23 ; + +param b := 1 36, 2 34, 3 38, 4 27, 5 33; + +param c : 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 := + 1 17 21 22 18 24 15 20 18 19 18 16 22 24 24 16 + 2 23 16 21 16 17 16 19 25 18 21 17 15 25 17 24 + 3 16 20 16 25 24 16 17 19 19 18 20 16 17 21 24 + 4 19 19 22 22 20 16 19 17 21 19 25 23 25 25 25 + 5 18 19 15 15 21 25 16 16 23 15 22 17 19 22 24 ; + +end;