diff -r d59bea55db9b -r c445c931472f examples/sql/transp_mysql.mod
--- /dev/null	Thu Jan 01 00:00:00 1970 +0000
+++ b/examples/sql/transp_mysql.mod	Mon Dec 06 13:09:21 2010 +0100
@@ -0,0 +1,71 @@
+# A TRANSPORTATION PROBLEM
+#
+# This problem finds a least cost shipping schedule that meets
+# requirements at markets and supplies at factories.
+#
+#  References:
+#              Dantzig G B, "Linear Programming and Extensions."
+#              Princeton University Press, Princeton, New Jersey, 1963,
+#              Chapter 3-3.
+
+set I;
+/* canning plants */
+
+param a{i in I};
+/* capacity of plant i in cases */
+
+table plants IN "MySQL"
+  'Database=glpk;UID=glpk;PWD=gnu'
+  'SELECT PLANT, CAPA AS CAPACITY FROM transp_capa' :
+   I <- [ PLANT ], a ~ CAPACITY;
+
+set J;
+/* markets */
+
+param b{j in J};
+/* demand at market j in cases */
+
+table markets IN "MySQL"
+  'Database=glpk;UID=glpk;PWD=gnu'
+  'transp_demand' :
+  J <- [ MARKET ], b ~ DEMAND;
+
+param d{i in I, j in J};
+/* distance in thousands of miles */
+
+table dist IN "MySQL"
+  'Database=glpk;UID=glpk;PWD=gnu'
+  'transp_dist' :
+  [ LOC1, LOC2 ], d ~ DIST;
+
+param f;
+/* freight in dollars per case per thousand miles */
+
+param c{i in I, j in J} := f * d[i,j] / 1000;
+/* transport cost in thousands of dollars per case */
+
+var x{i in I, j in J} >= 0;
+/* shipment quantities in cases */
+
+minimize cost: sum{i in I, j in J} c[i,j] * x[i,j];
+/* total transportation costs in thousands of dollars */
+
+s.t. supply{i in I}: sum{j in J} x[i,j] <= a[i];
+/* observe supply limit at plant i */
+
+s.t. demand{j in J}: sum{i in I} x[i,j] >= b[j];
+/* satisfy demand at market j */
+
+solve;
+
+table result{i in I, j in J: x[i,j]} OUT "MySQL"
+  'Database=glpk;UID=glpk;PWD=gnu'
+  'DELETE FROM transp_result;'
+  'INSERT INTO transp_result VALUES (?,?,?)' :
+  i ~ LOC1, j ~ LOC2, x[i,j] ~ QUANTITY;
+
+data;
+
+param f := 90;
+
+end;