5 #include <lemon/time_measure.h>
 
     6 #include <lp_solver_base.h>
 
    10 using namespace lemon;
 
    13   On an 1537Mhz PC, the run times with 
 
    14   glpk are the following.
 
    15   for n=3,4, some secondes
 
    19 int main(int, char **) {
 
    21   const double row_sum=(1.0+n*n)*n/2;
 
    24   typedef LPGLPK LPSolver;
 
    25   typedef LPSolver::Col Col;
 
    27   typedef std::map<std::pair<int, int>, Col> Coords;
 
    29   // we create a new variable for each entry 
 
    30   // of the magic square
 
    31   for (int i=1; i<=n; ++i) {
 
    32     for (int j=1; j<=n; ++j) { 
 
    34       x[std::make_pair(i,j)]=col;
 
    35       lp.setColLowerBound(col, 1.0);
 
    36       lp.setColUpperBound(col, double(n*n));
 
    39   LPSolver::Expression expr3, expr4;
 
    40   for (int i=1; i<=n; ++i) {
 
    41     LPSolver::Expression expr1, expr2;
 
    42     for (int j=1; j<=n; ++j) {
 
    43       expr1+=x[std::make_pair(i, j)];
 
    44       expr2+=x[std::make_pair(j, i)];
 
    46     // sum of rows and columns
 
    47     lp.addRow(expr1==row_sum);
 
    48     lp.addRow(expr2==row_sum);
 
    49     expr3+=x[std::make_pair(i, i)];
 
    50     expr4+=x[std::make_pair(i, (n+1)-i)];
 
    52   // sum of the diagonal entries
 
    53   lp.addRow(expr3==row_sum);
 
    54   lp.addRow(expr4==row_sum);
 
    56   cout << "elapsed time: " << ts << endl;
 
    57   for (int i=1; i<=n; ++i) {
 
    58     for (int j=1; j<=n; ++j) { 
 
    59       cout << "x("<<i<<","<<j<<")="<<lp.getPrimal(x[std::make_pair(i,j)]) 
 
    63   // we make new binary variables for each pair of 
 
    64   // entries of the square to achieve that 
 
    65   // the values of different entries are different
 
    67   for (Coords::const_iterator it=x.begin(); it!=x.end(); ++it) {
 
    68     Coords::const_iterator jt=it; ++jt;
 
    69     for(; jt!=x.end(); ++jt) {
 
    70       Col col1=(*it).second;
 
    71       Col col2=(*jt).second;
 
    73       lp.setColLowerBound(col, 0.0);
 
    74       lp.setColUpperBound(col, 1.0);
 
    75       lp.addRow(double(-n*n+1.0)<=1.0*col2-1.0*col1-double(n*n)*col<=-1.0);
 
    79   cout << "elapsed time: " << ts << endl;
 
    81   // let's solve the integer problem
 
    83   cout << "elapsed time: " << ts << endl;
 
    84   for (int i=1; i<=n; ++i) {
 
    85     for (int j=1; j<=n; ++j) { 
 
    86       cout << "x("<<i<<","<<j<<")="<<lp.getMIPPrimal(x[std::make_pair(i,j)])