doc/min_cost_flow.dox
changeset 783 ef88c0a30f85
parent 663 8b0df68370a4
child 788 c92296660262
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     1.2 +++ b/doc/min_cost_flow.dox	Thu Nov 05 15:48:01 2009 +0100
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     1.4 +/* -*- mode: C++; indent-tabs-mode: nil; -*-
     1.5 + *
     1.6 + * This file is a part of LEMON, a generic C++ optimization library.
     1.7 + *
     1.8 + * Copyright (C) 2003-2009
     1.9 + * Egervary Jeno Kombinatorikus Optimalizalasi Kutatocsoport
    1.10 + * (Egervary Research Group on Combinatorial Optimization, EGRES).
    1.11 + *
    1.12 + * Permission to use, modify and distribute this software is granted
    1.13 + * provided that this copyright notice appears in all copies. For
    1.14 + * precise terms see the accompanying LICENSE file.
    1.15 + *
    1.16 + * This software is provided "AS IS" with no warranty of any kind,
    1.17 + * express or implied, and with no claim as to its suitability for any
    1.18 + * purpose.
    1.19 + *
    1.20 + */
    1.21 +
    1.22 +namespace lemon {
    1.23 +
    1.24 +/**
    1.25 +\page min_cost_flow Minimum Cost Flow Problem
    1.26 +
    1.27 +\section mcf_def Definition (GEQ form)
    1.28 +
    1.29 +The \e minimum \e cost \e flow \e problem is to find a feasible flow of
    1.30 +minimum total cost from a set of supply nodes to a set of demand nodes
    1.31 +in a network with capacity constraints (lower and upper bounds)
    1.32 +and arc costs \ref amo93networkflows.
    1.33 +
    1.34 +Formally, let \f$G=(V,A)\f$ be a digraph, \f$lower: A\rightarrow\mathbf{R}\f$,
    1.35 +\f$upper: A\rightarrow\mathbf{R}\cup\{+\infty\}\f$ denote the lower and
    1.36 +upper bounds for the flow values on the arcs, for which
    1.37 +\f$lower(uv) \leq upper(uv)\f$ must hold for all \f$uv\in A\f$,
    1.38 +\f$cost: A\rightarrow\mathbf{R}\f$ denotes the cost per unit flow
    1.39 +on the arcs and \f$sup: V\rightarrow\mathbf{R}\f$ denotes the
    1.40 +signed supply values of the nodes.
    1.41 +If \f$sup(u)>0\f$, then \f$u\f$ is a supply node with \f$sup(u)\f$
    1.42 +supply, if \f$sup(u)<0\f$, then \f$u\f$ is a demand node with
    1.43 +\f$-sup(u)\f$ demand.
    1.44 +A minimum cost flow is an \f$f: A\rightarrow\mathbf{R}\f$ solution
    1.45 +of the following optimization problem.
    1.46 +
    1.47 +\f[ \min\sum_{uv\in A} f(uv) \cdot cost(uv) \f]
    1.48 +\f[ \sum_{uv\in A} f(uv) - \sum_{vu\in A} f(vu) \geq
    1.49 +    sup(u) \quad \forall u\in V \f]
    1.50 +\f[ lower(uv) \leq f(uv) \leq upper(uv) \quad \forall uv\in A \f]
    1.51 +
    1.52 +The sum of the supply values, i.e. \f$\sum_{u\in V} sup(u)\f$ must be
    1.53 +zero or negative in order to have a feasible solution (since the sum
    1.54 +of the expressions on the left-hand side of the inequalities is zero).
    1.55 +It means that the total demand must be greater or equal to the total
    1.56 +supply and all the supplies have to be carried out from the supply nodes,
    1.57 +but there could be demands that are not satisfied.
    1.58 +If \f$\sum_{u\in V} sup(u)\f$ is zero, then all the supply/demand
    1.59 +constraints have to be satisfied with equality, i.e. all demands
    1.60 +have to be satisfied and all supplies have to be used.
    1.61 +
    1.62 +
    1.63 +\section mcf_algs Algorithms
    1.64 +
    1.65 +LEMON contains several algorithms for solving this problem, for more
    1.66 +information see \ref min_cost_flow_algs "Minimum Cost Flow Algorithms".
    1.67 +
    1.68 +A feasible solution for this problem can be found using \ref Circulation.
    1.69 +
    1.70 +
    1.71 +\section mcf_dual Dual Solution
    1.72 +
    1.73 +The dual solution of the minimum cost flow problem is represented by
    1.74 +node potentials \f$\pi: V\rightarrow\mathbf{R}\f$.
    1.75 +An \f$f: A\rightarrow\mathbf{R}\f$ primal feasible solution is optimal
    1.76 +if and only if for some \f$\pi: V\rightarrow\mathbf{R}\f$ node potentials
    1.77 +the following \e complementary \e slackness optimality conditions hold.
    1.78 +
    1.79 + - For all \f$uv\in A\f$ arcs:
    1.80 +   - if \f$cost^\pi(uv)>0\f$, then \f$f(uv)=lower(uv)\f$;
    1.81 +   - if \f$lower(uv)<f(uv)<upper(uv)\f$, then \f$cost^\pi(uv)=0\f$;
    1.82 +   - if \f$cost^\pi(uv)<0\f$, then \f$f(uv)=upper(uv)\f$.
    1.83 + - For all \f$u\in V\f$ nodes:
    1.84 +   - \f$\pi(u)<=0\f$;
    1.85 +   - if \f$\sum_{uv\in A} f(uv) - \sum_{vu\in A} f(vu) \neq sup(u)\f$,
    1.86 +     then \f$\pi(u)=0\f$.
    1.87 + 
    1.88 +Here \f$cost^\pi(uv)\f$ denotes the \e reduced \e cost of the arc
    1.89 +\f$uv\in A\f$ with respect to the potential function \f$\pi\f$, i.e.
    1.90 +\f[ cost^\pi(uv) = cost(uv) + \pi(u) - \pi(v).\f]
    1.91 +
    1.92 +All algorithms provide dual solution (node potentials), as well,
    1.93 +if an optimal flow is found.
    1.94 +
    1.95 +
    1.96 +\section mcf_eq Equality Form
    1.97 +
    1.98 +The above \ref mcf_def "definition" is actually more general than the
    1.99 +usual formulation of the minimum cost flow problem, in which strict
   1.100 +equalities are required in the supply/demand contraints.
   1.101 +
   1.102 +\f[ \min\sum_{uv\in A} f(uv) \cdot cost(uv) \f]
   1.103 +\f[ \sum_{uv\in A} f(uv) - \sum_{vu\in A} f(vu) =
   1.104 +    sup(u) \quad \forall u\in V \f]
   1.105 +\f[ lower(uv) \leq f(uv) \leq upper(uv) \quad \forall uv\in A \f]
   1.106 +
   1.107 +However if the sum of the supply values is zero, then these two problems
   1.108 +are equivalent.
   1.109 +The \ref min_cost_flow_algs "algorithms" in LEMON support the general
   1.110 +form, so if you need the equality form, you have to ensure this additional
   1.111 +contraint manually.
   1.112 +
   1.113 +
   1.114 +\section mcf_leq Opposite Inequalites (LEQ Form)
   1.115 +
   1.116 +Another possible definition of the minimum cost flow problem is
   1.117 +when there are <em>"less or equal"</em> (LEQ) supply/demand constraints,
   1.118 +instead of the <em>"greater or equal"</em> (GEQ) constraints.
   1.119 +
   1.120 +\f[ \min\sum_{uv\in A} f(uv) \cdot cost(uv) \f]
   1.121 +\f[ \sum_{uv\in A} f(uv) - \sum_{vu\in A} f(vu) \leq
   1.122 +    sup(u) \quad \forall u\in V \f]
   1.123 +\f[ lower(uv) \leq f(uv) \leq upper(uv) \quad \forall uv\in A \f]
   1.124 +
   1.125 +It means that the total demand must be less or equal to the 
   1.126 +total supply (i.e. \f$\sum_{u\in V} sup(u)\f$ must be zero or
   1.127 +positive) and all the demands have to be satisfied, but there
   1.128 +could be supplies that are not carried out from the supply
   1.129 +nodes.
   1.130 +The equality form is also a special case of this form, of course.
   1.131 +
   1.132 +You could easily transform this case to the \ref mcf_def "GEQ form"
   1.133 +of the problem by reversing the direction of the arcs and taking the
   1.134 +negative of the supply values (e.g. using \ref ReverseDigraph and
   1.135 +\ref NegMap adaptors).
   1.136 +However \ref NetworkSimplex algorithm also supports this form directly
   1.137 +for the sake of convenience.
   1.138 +
   1.139 +Note that the optimality conditions for this supply constraint type are
   1.140 +slightly differ from the conditions that are discussed for the GEQ form,
   1.141 +namely the potentials have to be non-negative instead of non-positive.
   1.142 +An \f$f: A\rightarrow\mathbf{R}\f$ feasible solution of this problem
   1.143 +is optimal if and only if for some \f$\pi: V\rightarrow\mathbf{R}\f$
   1.144 +node potentials the following conditions hold.
   1.145 +
   1.146 + - For all \f$uv\in A\f$ arcs:
   1.147 +   - if \f$cost^\pi(uv)>0\f$, then \f$f(uv)=lower(uv)\f$;
   1.148 +   - if \f$lower(uv)<f(uv)<upper(uv)\f$, then \f$cost^\pi(uv)=0\f$;
   1.149 +   - if \f$cost^\pi(uv)<0\f$, then \f$f(uv)=upper(uv)\f$.
   1.150 + - For all \f$u\in V\f$ nodes:
   1.151 +   - \f$\pi(u)>=0\f$;
   1.152 +   - if \f$\sum_{uv\in A} f(uv) - \sum_{vu\in A} f(vu) \neq sup(u)\f$,
   1.153 +     then \f$\pi(u)=0\f$.
   1.154 +
   1.155 +*/
   1.156 +}