lemon-project-template-glpk
comparison deps/glpk/examples/food.mod @ 11:4fc6ad2fb8a6
Test GLPK in src/main.cc
author | Alpar Juttner <alpar@cs.elte.hu> |
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date | Sun, 06 Nov 2011 21:43:29 +0100 |
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-1:000000000000 | 0:aed88eb67128 |
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1 /* Food Manufacture 1, section 12.1 in | |
2 * Williams, "Model Building in Mathematical Programming" | |
3 * | |
4 * Sebastian Nowozin <nowozin@gmail.com> | |
5 */ | |
6 | |
7 set oils; | |
8 set month; | |
9 | |
10 /* Buying prices of the raw oils in the next six month. */ | |
11 param buyingprices{month,oils}; | |
12 | |
13 /* Actual amount bought in each month. */ | |
14 var buys{month,oils} >= 0; | |
15 | |
16 /* Stock for each oil. */ | |
17 var stock{month,oils} >= 0; | |
18 | |
19 /* Price of the produced product */ | |
20 param productprice >= 0; | |
21 param storagecost; | |
22 | |
23 param oilhardness{oils} >= 0; | |
24 | |
25 /* Actual amount of output oil produced in each month */ | |
26 var production{m in month} >= 0; | |
27 var useoil{m in month, o in oils} >= 0; | |
28 | |
29 maximize totalprofit: | |
30 sum{m in month} productprice*production[m] | |
31 - sum{m in month, o in oils} buyingprices[m,o]*buys[m,o] | |
32 - sum{m in month, o in oils} storagecost*stock[m,o]; | |
33 | |
34 /* Constraints */ | |
35 | |
36 /* 1. Starting stock */ | |
37 s.t. startstock{o in oils}: | |
38 stock[1,o] = 500; | |
39 s.t. endstock{o in oils}: | |
40 stock[6,o] + buys[6,o] - useoil[6,o] >= 500; | |
41 | |
42 /* 2. Stock constraints */ | |
43 s.t. stocklimit{m in month, o in oils}: | |
44 stock[m,o] <= 1000; | |
45 | |
46 s.t. production1{m in month, o in oils}: | |
47 useoil[m,o] <= stock[m,o] + buys[m,o]; | |
48 s.t. production2{m1 in month, m2 in month, o in oils : m2 = m1+1}: | |
49 stock[m2,o] = stock[m1,o] + buys[m1,o] - useoil[m1,o]; | |
50 | |
51 s.t. production3a{m in month}: | |
52 sum{o in oils} oilhardness[o]*useoil[m,o] >= 3*production[m]; | |
53 s.t. production3b{m in month}: | |
54 sum{o in oils} oilhardness[o]*useoil[m,o] <= 6*production[m]; | |
55 | |
56 s.t. production4{m in month}: | |
57 production[m] = sum{o in oils} useoil[m,o]; | |
58 | |
59 /* 3. Refining constraints */ | |
60 s.t. refine1{m in month}: | |
61 useoil[m,"VEG1"]+useoil[m,"VEG2"] <= 200; | |
62 s.t. refine2{m in month}: | |
63 useoil[m,"OIL1"]+useoil[m,"OIL2"]+useoil[m,"OIL3"] <= 250; | |
64 | |
65 solve; | |
66 | |
67 for {m in month} { | |
68 printf "Month %d\n", m; | |
69 printf "PRODUCE %4.2f tons, hardness %4.2f\n", production[m], | |
70 (sum{o in oils} oilhardness[o]*useoil[m,o]) / (sum{o in oils} useoil[m,o]); | |
71 | |
72 printf "\tVEG1\tVEG2\tOIL1\tOIL2\tOIL3\n"; | |
73 printf "STOCK"; | |
74 printf "%d", m; | |
75 for {o in oils} { | |
76 printf "\t%4.2f", stock[m,o]; | |
77 } | |
78 printf "\nBUY"; | |
79 for {o in oils} { | |
80 printf "\t%4.2f", buys[m,o]; | |
81 } | |
82 printf "\nUSE"; | |
83 printf "%d", m; | |
84 for {o in oils} { | |
85 printf "\t%4.2f", useoil[m,o]; | |
86 } | |
87 printf "\n"; | |
88 printf "\n"; | |
89 } | |
90 printf "Total profit: %4.2f\n", | |
91 (sum{m in month} productprice*production[m] | |
92 - sum{m in month, o in oils} buyingprices[m,o]*buys[m,o] | |
93 - sum{m in month, o in oils} storagecost*stock[m,o]); | |
94 printf " turnover: %4.2f\n", | |
95 sum{m in month} productprice*production[m]; | |
96 printf " buying costs: %4.2f\n", | |
97 sum{m in month, o in oils} buyingprices[m,o]*buys[m,o]; | |
98 printf " storage costs: %4.2f\n", | |
99 sum{m in month, o in oils} storagecost*stock[m,o]; | |
100 | |
101 | |
102 data; | |
103 | |
104 param : oils : oilhardness := | |
105 VEG1 8.8 | |
106 VEG2 6.1 | |
107 OIL1 2.0 | |
108 OIL2 4.2 | |
109 OIL3 5.0 ; | |
110 | |
111 set month := 1 2 3 4 5 6; | |
112 | |
113 param buyingprices | |
114 | |
115 : VEG1 VEG2 OIL1 OIL2 OIL3 := | |
116 | |
117 1 110 120 130 110 115 | |
118 2 130 130 110 90 115 | |
119 3 110 140 130 100 95 | |
120 4 120 110 120 120 125 | |
121 5 100 120 150 110 105 | |
122 6 90 100 140 80 135 ; | |
123 | |
124 param productprice := 150; | |
125 param storagecost := 5; | |
126 | |
127 end; |