demo/mip_demo.cc
author Peter Kovacs <kpeter@inf.elte.hu>
Mon, 01 Mar 2010 02:28:05 +0100
changeset 56 11bd4cea8379
permissions -rw-r--r--
Slightly extend LGF section
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/* -*- mode: C++; indent-tabs-mode: nil; -*-
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 *
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 * This file is a part of LEMON, a generic C++ optimization library.
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 *
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 * Copyright (C) 2003-2010
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 * Egervary Jeno Kombinatorikus Optimalizalasi Kutatocsoport
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 * (Egervary Research Group on Combinatorial Optimization, EGRES).
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 *
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 * Permission to use, modify and distribute this software is granted
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 * provided that this copyright notice appears in all copies. For
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 * precise terms see the accompanying LICENSE file.
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 *
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 * This software is provided "AS IS" with no warranty of any kind,
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 * express or implied, and with no claim as to its suitability for any
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 * purpose.
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 *
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 */
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///\file
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///\brief Demo program for the MIP solver interface.
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///
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/// This demo program shows how the LEMON MIP solver interface can be used.
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/// A simple mixed integer programming (MIP) problem is formulated and solved
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/// using the default MIP solver (e.g. GLPK).
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///
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/// \include mip_demo.cc
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#include <iostream>
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#include <lemon/lp.h>
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using namespace lemon;
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int main()
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{
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  // Create an instance of the default MIP solver class
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  // (it will represent an "empty" problem at first)
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  Mip mip;
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  // Add two columns (variables) to the problem
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  Mip::Col x1 = mip.addCol();
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  Mip::Col x2 = mip.addCol();
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  // Add rows (constraints) to the problem
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  mip.addRow(x1 - 5 <= x2);
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  mip.addRow(0 <= 2 * x1 + x2 <= 25);
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  // Set lower and upper bounds for the columns (variables)
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  mip.colLowerBound(x1, 0);
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  mip.colUpperBound(x2, 10);
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  // Set the type of the columns
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  mip.colType(x1, Mip::INTEGER);
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  mip.colType(x2, Mip::REAL);
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  // Specify the objective function
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  mip.max();
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  mip.obj(5 * x1 + 3 * x2);
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  // Solve the problem using the underlying MIP solver
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  mip.solve();
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  // Print the results
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  if (mip.type() == Mip::OPTIMAL) {
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    std::cout << "Objective function value: " << mip.solValue() << std::endl;
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    std::cout << "x1 = " << mip.sol(x1) << std::endl;
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    std::cout << "x2 = " << mip.sol(x2) << std::endl;
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  } else {
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    std::cout << "Optimal solution not found." << std::endl;
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  }
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  return 0;
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}