%* glpk04.tex *% \chapter{Advanced API Routines} \section{Background} \label{basbgd} Using vector and matrix notations LP problem (1.1)---(1.3) (see Section \ref{seclp}, page \pageref{seclp}) can be stated as follows: \medskip \noindent \hspace{.5in} minimize (or maximize) $$z=c^Tx_S+c_0\eqno(3.1)$$ \hspace{.5in} subject to linear constraints $$x_R=Ax_S\eqno(3.2)$$ \hspace{.5in} and bounds of variables $$ \begin{array}{l@{\ }c@{\ }l@{\ }c@{\ }l} l_R&\leq&x_R&\leq&u_R\\ l_S&\leq&x_S&\leq&u_S\\ \end{array}\eqno(3.3) $$ where: \noindent $x_R=(x_1,\dots,x_m)$ is the vector of auxiliary variables; \noindent $x_S=(x_{m+1},\dots,x_{m+n})$ is the vector of structural variables; \noindent $z$ is the objective function; \noindent $c=(c_1,\dots,c_n)$ is the vector of objective coefficients; \noindent $c_0$ is the constant term (``shift'') of the objective function; \noindent $A=(a_{11},\dots,a_{mn})$ is the constraint matrix; \noindent $l_R=(l_1,\dots,l_m)$ is the vector of lower bounds of auxiliary variables; \noindent $u_R=(u_1,\dots,u_m)$ is the vector of upper bounds of auxiliary variables; \noindent $l_S=(l_{m+1},\dots,l_{m+n})$ is the vector of lower bounds of structural variables; \noindent $u_S=(u_{m+1},\dots,u_{m+n})$ is the vector of upper bounds of structural variables. \medskip From the simplex method's standpoint there is no difference between auxiliary and structural variables. This allows combining all these variables into one vector that leads to the following problem statement: \medskip \noindent \hspace{.5in} minimize (or maximize) $$z=(0\ |\ c)^Tx+c_0\eqno(3.4)$$ \hspace{.5in} subject to linear constraints $$(I\ |-\!A)x=0\eqno(3.5)$$ \hspace{.5in} and bounds of variables $$l\leq x\leq u\eqno(3.6)$$ where: \noindent $x=(x_R\ |\ x_S)$ is the $(m+n)$-vector of (all) variables; \noindent $(0\ |\ c)$ is the $(m+n)$-vector of objective coefficients;\footnote{Subvector 0 corresponds to objective coefficients at auxiliary variables.} \noindent $(I\ |-\!A)$ is the {\it augmented} constraint $m\times(m+n)$-matrix;\footnote{Note that due to auxiliary variables matrix $(I\ |-\!A)$ contains the unity submatrix and therefore has full rank. This means, in particular, that the system (3.5) has no linearly dependent constraints.} \noindent $l=(l_R\ |\ l_S)$ is the $(m+n)$-vector of lower bounds of (all) variables; \noindent $u=(u_R\ |\ u_S)$ is the $(m+n)$-vector of upper bounds of (all) variables. \medskip By definition an {\it LP basic solution} geometrically is a point in the space of all variables, which is the intersection of planes corresponding to active constraints\footnote{A constraint is called {\it active} if in a given point it is satisfied as equality, otherwise it is called {\it inactive}.}. The space of all variables has the dimension $m+n$, therefore, to define some basic solution we have to define $m+n$ active constraints. Note that $m$ constraints (3.5) being linearly independent equalities are always active, so remaining $n$ active constraints can be chosen only from bound constraints (3.6). A variable is called {\it non-basic}, if its (lower or upper) bound is active, otherwise it is called {\it basic}. Since, as was said above, exactly $n$ bound constraints must be active, in any basic solution there are always $n$ non-basic variables and $m$ basic variables. (Note that a free variable also can be non-basic. Although such variable has no bounds, we can think it as the difference between two non-negative variables, which both are non-basic in this case.) Now consider how to determine numeric values of all variables for a given basic solution. Let $\Pi$ be an appropriate permutation matrix of the order $(m+n)$. Then we can write: $$\left(\begin{array}{@{}c@{}}x_B\\x_N\\\end{array}\right)= \Pi\left(\begin{array}{@{}c@{}}x_R\\x_S\\\end{array}\right)=\Pi x, \eqno(3.7)$$ where $x_B$ is the vector of basic variables, $x_N$ is the vector of non-basic variables, $x=(x_R\ |\ x_S)$ is the vector of all variables in the original order. In this case the system of linear constraints (3.5) can be rewritten as follows: $$(I\ |-\!A)\Pi^T\Pi x=0\ \ \ \Rightarrow\ \ \ (B\ |\ N) \left(\begin{array}{@{}c@{}}x_B\\x_N\\\end{array}\right)=0,\eqno(3.8)$$ where $$(B\ |\ N)=(I\ |-\!A)\Pi^T.\eqno(3.9)$$ Matrix $B$ is a square non-singular $m\times m$-matrix, which is composed from columns of the augmented constraint matrix corresponding to basic variables. It is called the {\it basis matrix} or simply the {\it basis}. Matrix $N$ is a rectangular $m\times n$-matrix, which is composed from columns of the augmented constraint matrix corresponding to non-basic variables. From (3.8) it follows that: $$Bx_B+Nx_N=0,\eqno(3.10)$$ therefore, $$x_B=-B^{-1}Nx_N.\eqno(3.11)$$ Thus, the formula (3.11) shows how to determine numeric values of basic variables $x_B$ assuming that non-basic variables $x_N$ are fixed on their active bounds. The $m\times n$-matrix $$\Xi=-B^{-1}N,\eqno(3.12)$$ which appears in (3.11), is called the {\it simplex tableau}.\footnote{This definition corresponds to the GLPK implementation.} It shows how basic variables depend on non-basic variables: $$x_B=\Xi x_N.\eqno(3.13)$$ The system (3.13) is equivalent to the system (3.5) in the sense that they both define the same set of points in the space of (primal) variables, which satisfy to these systems. If, moreover, values of all basic variables satisfy to their bound constraints (3.3), the corresponding basic solution is called {\it (primal) feasible}, otherwise {\it (primal) infeasible}. It is understood that any (primal) feasible basic solution satisfy to all constraints (3.2) and (3.3). The LP theory says that if LP has optimal solution, it has (at least one) basic feasible solution, which corresponds to the optimum. And the most natural way to determine whether a given basic solution is optimal or not is to use the Karush---Kuhn---Tucker optimality conditions. \def\arraystretch{1.5} For the problem statement (3.4)---(3.6) the optimality conditions are the following:\footnote{These conditions can be appiled to any solution, not only to a basic solution.} $$(I\ |-\!A)x=0\eqno(3.14)$$ $$(I\ |-\!A)^T\pi+\lambda_l+\lambda_u=\nabla z=(0\ |\ c)^T\eqno(3.15)$$ $$l\leq x\leq u\eqno(3.16)$$ $$\lambda_l\geq 0,\ \ \lambda_u\leq 0\ \ \mbox{(minimization)} \eqno(3.17)$$ $$\lambda_l\leq 0,\ \ \lambda_u\geq 0\ \ \mbox{(maximization)} \eqno(3.18)$$ $$(\lambda_l)_k(x_k-l_k)=0,\ \ (\lambda_u)_k(x_k-u_k)=0,\ \ k=1,2,\dots, m+n\eqno(3.19)$$ where: $\pi=(\pi_1,\pi_2,\dots,\pi_m)$ is a $m$-vector of Lagrange multipliers for equality constraints (3.5); $\lambda_l=[(\lambda_l)_1,(\lambda_l)_2,\dots,(\lambda_l)_n]$ is a $n$-vector of Lagrange multipliers for lower bound constraints (3.6); $\lambda_u=[(\lambda_u)_1,(\lambda_u)_2,\dots,(\lambda_u)_n]$ is a $n$-vector of Lagrange multipliers for upper bound constraints (3.6). Condition (3.14) is the {\it primal} (original) system of equality constraints (3.5). Condition (3.15) is the {\it dual} system of equality constraints. It requires the gradient of the objective function to be a linear combination of normals to the planes defined by constraints of the original problem. Condition (3.16) is the primal (original) system of bound constraints (3.6). Condition (3.17) (or (3.18) in case of maximization) is the dual system of bound constraints. Condition (3.19) is the {\it complementary slackness condition}. It requires, for each original (auxiliary or structural) variable $x_k$, that either its (lower or upper) bound must be active, or zero bound of the corresponding Lagrange multiplier ($(\lambda_l)_k$ or $(\lambda_u)_k$) must be active. In GLPK two multipliers $(\lambda_l)_k$ and $(\lambda_u)_k$ for each primal (original) variable $x_k$, $k=1,2,\dots,m+n$, are combined into one multiplier: $$\lambda_k=(\lambda_l)_k+(\lambda_u)_k,\eqno(3.20)$$ which is called a {\it dual variable} for $x_k$. This {\it cannot} lead to the ambiguity, because both lower and upper bounds of $x_k$ cannot be active at the same time,\footnote{If $x_k$ is a fixed variable, we can think it as double-bounded variable $l_k\leq x_k\leq u_k$, where $l_k=u_k.$} so at least one of $(\lambda_l)_k$ and $(\lambda_u)_k$ must be equal to zero, and because these multipliers have different signs, the combined multiplier, which is their sum, uniquely defines each of them. \def\arraystretch{1} Using dual variables $\lambda_k$ the dual system of bound constraints (3.17) and (3.18) can be written in the form of so called {\it ``rule of signs''} as follows: \begin{center} \begin{tabular}{|@{\,}c@{$\,$}|@{$\,$}c@{$\,$}|@{$\,$}c@{$\,$}| @{$\,$}c|c@{$\,$}|@{$\,$}c@{$\,$}|@{$\,$}c@{$\,$}|} \hline Original bound&\multicolumn{3}{c|}{Minimization}&\multicolumn{3}{c|} {Maximization}\\ \cline{2-7} constraint&$(\lambda_l)_k$&$(\lambda_u)_k$&$(\lambda_l)_k+ (\lambda_u)_k$&$(\lambda_l)_k$&$(\lambda_u)_k$&$(\lambda_l)_k+ (\lambda_u)_k$\\ \hline $-\infty= {\tt piv\_tol}\cdot\max|u_{i*}|$, i.e. if it is not very small in the magnitude among other elements in the same row. Decreasing this parameter may lead to better sparsity at the expense of numerical accuracy, and vice versa.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt int piv\_lim} (default: {\tt 4})} \\ &This parameter is used on computing $LU$-factorization of the basis matrix and specifies how many pivot candidates needs to be considered on choosing a pivot element, \verb|piv_lim| $\geq$ 1. If \verb|piv_lim| candidates have been considered, the pivoting routine prematurely terminates the search with the best candidate found.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt int suhl} (default: {\tt GLP\_ON})} \\ &This parameter is used on computing $LU$-factorization of the basis matrix. Being set to {\tt GLP\_ON} it enables applying the following heuristic proposed by Uwe Suhl: if a column of the active submatrix has no eligible pivot candidates, it is no more considered until it becomes a column singleton. In many cases this allows reducing the time needed for pivot searching. To disable this heuristic the parameter \verb|suhl| should be set to {\tt GLP\_OFF}.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt double eps\_tol} (default: {\tt 1e-15})} \\ &Epsilon tolerance, \verb|eps_tol| $\geq$ 0, used on computing $LU$-factorization of the basis matrix. If an element of the active submatrix of factor $U$ is less than \verb|eps_tol| in the magnitude, it is replaced by exact zero.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt double max\_gro} (default: {\tt 1e+10})} \\ &Maximal growth of elements of factor $U$, \verb|max_gro| $\geq$ 1, allowable on computing $LU$-factorization of the basis matrix. If on some elimination step the ratio $u_{big}/b_{max}$ (where $u_{big}$ is the largest magnitude of elements of factor $U$ appeared in its active submatrix during all the factorization process, $b_{max}$ is the largest magnitude of elements of the basis matrix to be factorized), the basis matrix is considered as ill-conditioned.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt int nfs\_max} (default: {\tt 100})} \\ &Maximal number of additional row-like factors (entries of the eta file), \verb|nfs_max| $\geq$ 1, which can be added to $LU$-factorization of the basis matrix on updating it with the Forrest--Tomlin technique. This parameter is used only once, before $LU$-factorization is computed for the first time, to allocate working arrays. As a rule, each update adds one new factor (however, some updates may need no addition), so this parameter limits the number of updates between refactorizations.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt double upd\_tol} (default: {\tt 1e-6})} \\ &Update tolerance, 0 $<$ \verb|upd_tol| $<$ 1, used on updating $LU$-factorization of the basis matrix with the Forrest--Tomlin technique. If after updating the magnitude of some diagonal element $u_{kk}$ of factor $U$ becomes less than ${\tt upd\_tol}\cdot\max(|u_{k*}|, |u_{*k}|)$, the factorization is considered as inaccurate.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt int nrs\_max} (default: {\tt 100})} \\ &Maximal number of additional rows and columns, \verb|nrs_max| $\geq$ 1, which can be added to $LU$-factorization of the basis matrix on updating it with the Schur complement technique. This parameter is used only once, before $LU$-factorization is computed for the first time, to allocate working arrays. As a rule, each update adds one new row and column (however, some updates may need no addition), so this parameter limits the number of updates between refactorizations.\\ \end{tabular} \medskip \noindent\begin{tabular}{@{}p{17pt}@{}p{120.5mm}@{}} \multicolumn{2}{@{}l}{{\tt int rs\_size} (default: {\tt 0})} \\ &The initial size of the Sparse Vector Area, in non-zeros, used to store non-zero elements of additional rows and columns introduced on updating $LU$-factorization of the basis matrix with the Schur complement technique. If this parameter is set to 0, the initial SVA size is determined automatically.\\ \end{tabular} %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \newpage \subsection{glp\_get\_bhead---retrieve the basis header information} \subsubsection*{Synopsis} \begin{verbatim} int glp_get_bhead(glp_prob *lp, int k); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_get_bhead| returns the basis header information for the current basis associated with the specified problem object. \subsubsection*{Returns} If basic variable $(x_B)_k$, $1\leq k\leq m$, is $i$-th auxiliary variable ($1\leq i\leq m$), the routine returns $i$. Otherwise, if $(x_B)_k$ is $j$-th structural variable ($1\leq j\leq n$), the routine returns $m+j$. Here $m$ is the number of rows and $n$ is the number of columns in the problem object. \subsubsection*{Comments} Sometimes the application program may need to know which original (auxiliary and structural) variable correspond to a given basic variable, or, that is the same, which column of the augmented constraint matrix $(I\ |-\!A)$ correspond to a given column of the basis matrix $B$. \def\arraystretch{1} The correspondence is defined as follows:\footnote{For more details see Subsection \ref{basbgd}, page \pageref{basbgd}.} $$\left(\begin{array}{@{}c@{}}x_B\\x_N\\\end{array}\right)= \Pi\left(\begin{array}{@{}c@{}}x_R\\x_S\\\end{array}\right) \ \ \Leftrightarrow \ \ \left(\begin{array}{@{}c@{}}x_R\\x_S\\\end{array}\right)= \Pi^T\left(\begin{array}{@{}c@{}}x_B\\x_N\\\end{array}\right),$$ where $x_B$ is the vector of basic variables, $x_N$ is the vector of non-basic variables, $x_R$ is the vector of auxiliary variables following in their original order,\footnote{The original order of auxiliary and structural variables is defined by the ordinal numbers of corresponding rows and columns in the problem object.} $x_S$ is the vector of structural variables following in their original order, $\Pi$ is a permutation matrix (which is a component of the basis factorization). Thus, if $(x_B)_k=(x_R)_i$ is $i$-th auxiliary variable, the routine returns $i$, and if $(x_B)_k=(x_S)_j$ is $j$-th structural variable, the routine returns $m+j$, where $m$ is the number of rows in the problem object. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \newpage \subsection{glp\_get\_row\_bind---retrieve row index in the basis\\ header} \subsubsection*{Synopsis} \begin{verbatim} int glp_get_row_bind(glp_prob *lp, int i); \end{verbatim} \subsubsection*{Returns} The routine \verb|glp_get_row_bind| returns the index $k$ of basic variable $(x_B)_k$, $1\leq k\leq m$, which is $i$-th auxiliary variable (that is, the auxiliary variable corresponding to $i$-th row), $1\leq i\leq m$, in the current basis associated with the specified problem object, where $m$ is the number of rows. However, if $i$-th auxiliary variable is non-basic, the routine returns zero. \subsubsection*{Comments} The routine \verb|glp_get_row_bind| is an inverse to the routine \verb|glp_get_bhead|: if \verb|glp_get_bhead|$(lp,k)$ returns $i$, \verb|glp_get_row_bind|$(lp,i)$ returns $k$, and vice versa. \subsection{glp\_get\_col\_bind---retrieve column index in the basis header} \subsubsection*{Synopsis} \begin{verbatim} int glp_get_col_bind(glp_prob *lp, int j); \end{verbatim} \subsubsection*{Returns} The routine \verb|glp_get_col_bind| returns the index $k$ of basic variable $(x_B)_k$, $1\leq k\leq m$, which is $j$-th structural variable (that is, the structural variable corresponding to $j$-th column), $1\leq j\leq n$, in the current basis associated with the specified problem object, where $m$ is the number of rows, $n$ is the number of columns. However, if $j$-th structural variable is non-basic, the routine returns zero. \subsubsection*{Comments} The routine \verb|glp_get_col_bind| is an inverse to the routine \verb|glp_get_bhead|: if \verb|glp_get_bhead|$(lp,k)$ returns $m+j$, \verb|glp_get_col_bind|$(lp,j)$ returns $k$, and vice versa. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \newpage \subsection{glp\_ftran---perform forward transformation} \subsubsection*{Synopsis} \begin{verbatim} void glp_ftran(glp_prob *lp, double x[]); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_ftran| performs forward transformation (FTRAN), i.e. it solves the system $Bx=b$, where $B$ is the basis matrix associated with the specified problem object, $x$ is the vector of unknowns to be computed, $b$ is the vector of right-hand sides. On entry to the routine elements of the vector $b$ should be stored in locations \verb|x[1]|, \dots, \verb|x[m]|, where $m$ is the number of rows. On exit the routine stores elements of the vector $x$ in the same locations. \subsection{glp\_btran---perform backward transformation} \subsubsection*{Synopsis} \begin{verbatim} void glp_btran(glp_prob *lp, double x[]); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_btran| performs backward transformation (BTRAN), i.e. it solves the system $B^Tx=b$, where $B^T$ is a matrix transposed to the basis matrix $B$ associated with the specified problem object, $x$ is the vector of unknowns to be computed, $b$ is the vector of right-hand sides. On entry to the routine elements of the vector $b$ should be stored in locations \verb|x[1]|, \dots, \verb|x[m]|, where $m$ is the number of rows. On exit the routine stores elements of the vector $x$ in the same locations. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \newpage \subsection{glp\_warm\_up---``warm up'' LP basis} \subsubsection*{Synopsis} \begin{verbatim} int glp_warm_up(glp_prob *P); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_warm_up| ``warms up'' the LP basis for the specified problem object using current statuses assigned to rows and columns (that is, to auxiliary and structural variables). This operation includes computing factorization of the basis matrix (if it does not exist), computing primal and dual components of basic solution, and determining the solution status. \subsubsection*{Returns} \begin{tabular}{@{}p{25mm}p{97.3mm}@{}} 0 & The operation has been successfully performed.\\ \verb|GLP_EBADB| & The basis matrix is invalid, because the number of basic (auxiliary and structural) variables is not the same as the number of rows in the problem object.\\ \verb|GLP_ESING| & The basis matrix is singular within the working precision.\\ \verb|GLP_ECOND| & The basis matrix is ill-conditioned, i.e. its condition number is too large.\\ \end{tabular} %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \newpage \section{Simplex tableau routines} \subsection{glp\_eval\_tab\_row---compute row of the tableau} \subsubsection*{Synopsis} \begin{verbatim} int glp_eval_tab_row(glp_prob *lp, int k, int ind[], double val[]); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_eval_tab_row| computes a row of the current simplex tableau (see Subsection 3.1.1, formula (3.12)), which (row) corresponds to some basic variable specified by the parameter $k$ as follows: if $1\leq k\leq m$, the basic variable is $k$-th auxiliary variable, and if $m+1\leq k\leq m+n$, the basic variable is $(k-m)$-th structural variable, where $m$ is the number of rows and $n$ is the number of columns in the specified problem object. The basis factorization must exist. The computed row shows how the specified basic variable depends on non-basic variables: $$x_k=(x_B)_i=\xi_{i1}(x_N)_1+\xi_{i2}(x_N)_2+\dots+\xi_{in}(x_N)_n,$$ where $\xi_{i1}$, $\xi_{i2}$, \dots, $\xi_{in}$ are elements of the simplex table row, $(x_N)_1$, $(x_N)_2$, \dots, $(x_N)_n$ are non-basic (auxiliary and structural) variables. The routine stores column indices and corresponding numeric values of non-zero elements of the computed row in unordered sparse format in locations \verb|ind[1]|, \dots, \verb|ind[len]| and \verb|val[1]|, \dots, \verb|val[len]|, respectively, where $0\leq{\tt len}\leq n$ is the number of non-zero elements in the row returned on exit. Element indices stored in the array \verb|ind| have the same sense as index $k$, i.e. indices 1 to $m$ denote auxiliary variables while indices $m+1$ to $m+n$ denote structural variables (all these variables are obviously non-basic by definition). \subsubsection*{Returns} The routine \verb|glp_eval_tab_row| returns \verb|len|, which is the number of non-zero elements in the simplex table row stored in the arrays \verb|ind| and \verb|val|. \subsubsection*{Comments} A row of the simplex table is computed as follows. At first, the routine checks that the specified variable $x_k$ is basic and uses the permutation matrix $\Pi$ (3.7) to determine index $i$ of basic variable $(x_B)_i$, which corresponds to $x_k$. The row to be computed is $i$-th row of the matrix $\Xi$ (3.12), therefore: $$\xi_i=e_i^T\Xi=-e_i^TB^{-1}N=-(B^{-T}e_i)^TN,$$ where $e_i$ is $i$-th unity vector. So the routine performs BTRAN to obtain $i$-th row of the inverse $B^{-1}$: $$\varrho_i=B^{-T}e_i,$$ and then computes elements of the simplex table row as inner products: $$\xi_{ij}=-\varrho_i^TN_j,\ \ j=1,2,\dots,n,$$ where $N_j$ is $j$-th column of matrix $N$ (3.9), which (column) corresponds to non-basic variable $(x_N)_j$. The permutation matrix $\Pi$ is used again to convert indices $j$ of non-basic columns to original ordinal numbers of auxiliary and structural variables. \subsection{glp\_eval\_tab\_col---compute column of the tableau} \subsubsection*{Synopsis} \begin{verbatim} int glp_eval_tab_col(glp_prob *lp, int k, int ind[], double val[]); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_eval_tab_col| computes a column of the current simplex tableau (see Subsection 3.1.1, formula (3.12)), which (column) corresponds to some non-basic variable specified by the parameter $k$: if $1\leq k\leq m$, the non-basic variable is $k$-th auxiliary variable, and if $m+1\leq k\leq m+n$, the non-basic variable is $(k-m)$-th structural variable, where $m$ is the number of rows and $n$ is the number of columns in the specified problem object. The basis factorization must exist. The computed column shows how basic variables depends on the specified non-basic variable $x_k=(x_N)_j$: $$ \begin{array}{r@{\ }c@{\ }l@{\ }l} (x_B)_1&=&\dots+\xi_{1j}(x_N)_j&+\dots\\ (x_B)_2&=&\dots+\xi_{2j}(x_N)_j&+\dots\\ .\ \ .&.&.\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\\ (x_B)_m&=&\dots+\xi_{mj}(x_N)_j&+\dots\\ \end{array} $$ where $\xi_{1j}$, $\xi_{2j}$, \dots, $\xi_{mj}$ are elements of the simplex table column, $(x_B)_1$, $(x_B)_2$, \dots, $(x_B)_m$ are basic (auxiliary and structural) variables. The routine stores row indices and corresponding numeric values of non-zero elements of the computed column in unordered sparse format in locations \verb|ind[1]|, \dots, \verb|ind[len]| and \verb|val[1]|, \dots, \verb|val[len]|, respectively, where $0\leq{\tt len}\leq m$ is the number of non-zero elements in the column returned on exit. Element indices stored in the array \verb|ind| have the same sense as index $k$, i.e. indices 1 to $m$ denote auxiliary variables while indices $m+1$ to $m+n$ denote structural variables (all these variables are obviously basic by definition). \subsubsection*{Returns} The routine \verb|glp_eval_tab_col| returns \verb|len|, which is the number of non-zero elements in the simplex table column stored in the arrays \verb|ind| and \verb|val|. \subsubsection*{Comments} A column of the simplex table is computed as follows. At first, the routine checks that the specified variable $x_k$ is non-basic and uses the permutation matrix $\Pi$ (3.7) to determine index $j$ of non-basic variable $(x_N)_j$, which corresponds to $x_k$. The column to be computed is $j$-th column of the matrix $\Xi$ (3.12), therefore: $$\Xi_j=\Xi e_j=-B^{-1}Ne_j=-B^{-1}N_j,$$ where $e_j$ is $j$-th unity vector, $N_j$ is $j$-th column of matrix $N$ (3.9). So the routine performs FTRAN to transform $N_j$ to the simplex table column $\Xi_j=(\xi_{ij})$ and uses the permutation matrix $\Pi$ to convert row indices $i$ to original ordinal numbers of auxiliary and structural variables. \newpage \subsection{glp\_transform\_row---transform explicitly specified\\ row} \subsubsection*{Synopsis} \begin{verbatim} int glp_transform_row(glp_prob *P, int len, int ind[], double val[]); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_transform_row| performs the same operation as the routine \verb|glp_eval_tab_row| with exception that the row to be transformed is specified explicitly as a sparse vector. The explicitly specified row may be thought as a linear form: $$x=a_1x_{m+1}+a_2x_{m+2}+\dots+a_nx_{m+n},$$ where $x$ is an auxiliary variable for this row, $a_j$ are coefficients of the linear form, $x_{m+j}$ are structural variables. On entry column indices and numerical values of non-zero coefficients $a_j$ of the specified row should be placed in locations \verb|ind[1]|, \dots, \verb|ind[len]| and \verb|val[1]|, \dots, \verb|val[len]|, where \verb|len| is number of non-zero coefficients. This routine uses the system of equality constraints and the current basis in order to express the auxiliary variable $x$ through the current non-basic variables (as if the transformed row were added to the problem object and the auxiliary variable $x$ were basic), i.e. the resultant row has the form: $$x=\xi_1(x_N)_1+\xi_2(x_N)_2+\dots+\xi_n(x_N)_n,$$ where $\xi_j$ are influence coefficients, $(x_N)_j$ are non-basic (auxiliary and structural) variables, $n$ is the number of columns in the problem object. On exit the routine stores indices and numerical values of non-zero coefficients $\xi_j$ of the resultant row in locations \verb|ind[1]|, \dots, \verb|ind[len']| and \verb|val[1]|, \dots, \verb|val[len']|, where $0\leq{\tt len'}\leq n$ is the number of non-zero coefficients in the resultant row returned by the routine. Note that indices of non-basic variables stored in the array \verb|ind| correspond to original ordinal numbers of variables: indices 1 to $m$ mean auxiliary variables and indices $m+1$ to $m+n$ mean structural ones. \subsubsection*{Returns} The routine \verb|glp_transform_row| returns \verb|len'|, the number of non-zero coefficients in the resultant row stored in the arrays \verb|ind| and \verb|val|. \subsection{glp\_transform\_col---transform explicitly specified\\ column} \subsubsection*{Synopsis} \begin{verbatim} int glp_transform_col(glp_prob *P, int len, int ind[], double val[]); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_transform_col| performs the same operation as the routine \verb|glp_eval_tab_col| with exception that the column to be transformed is specified explicitly as a sparse vector. The explicitly specified column may be thought as it were added to the original system of equality constraints: $$ \begin{array}{l@{\ }c@{\ }r@{\ }c@{\ }r@{\ }c@{\ }r} x_1&=&a_{11}x_{m+1}&+\dots+&a_{1n}x_{m+n}&+&a_1x \\ x_2&=&a_{21}x_{m+1}&+\dots+&a_{2n}x_{m+n}&+&a_2x \\ \multicolumn{7}{c} {.\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .\ \ .}\\ x_m&=&a_{m1}x_{m+1}&+\dots+&a_{mn}x_{m+n}&+&a_mx \\ \end{array} $$ where $x_i$ are auxiliary variables, $x_{m+j}$ are structural variables (presented in the problem object), $x$ is a structural variable for the explicitly specified column, $a_i$ are constraint coefficients at $x$. On entry row indices and numerical values of non-zero coefficients $a_i$ of the specified column should be placed in locations \verb|ind[1]|, \dots, \verb|ind[len]| and \verb|val[1]|, \dots, \verb|val[len]|, where \verb|len| is number of non-zero coefficients. This routine uses the system of equality constraints and the current basis in order to express the current basic variables through the structural variable $x$ (as if the transformed column were added to the problem object and the variable $x$ were non-basic): $$ \begin{array}{l@{\ }c@{\ }r} (x_B)_1&=\dots+&\xi_{1}x\\ (x_B)_2&=\dots+&\xi_{2}x\\ \multicolumn{3}{c}{.\ \ .\ \ .\ \ .\ \ .\ \ .}\\ (x_B)_m&=\dots+&\xi_{m}x\\ \end{array} $$ where $\xi_i$ are influence coefficients, $x_B$ are basic (auxiliary and structural) variables, $m$ is the number of rows in the problem object. On exit the routine stores indices and numerical values of non-zero coefficients $\xi_i$ of the resultant column in locations \verb|ind[1]|, \dots, \verb|ind[len']| and \verb|val[1]|, \dots, \verb|val[len']|, where $0\leq{\tt len'}\leq m$ is the number of non-zero coefficients in the resultant column returned by the routine. Note that indices of basic variables stored in the array \verb|ind| correspond to original ordinal numbers of variables, i.e. indices 1 to $m$ mean auxiliary variables, indices $m+1$ to $m+n$ mean structural ones. \subsubsection*{Returns} The routine \verb|glp_transform_col| returns \verb|len'|, the number of non-zero coefficients in the resultant column stored in the arrays \verb|ind| and \verb|val|. \subsection{glp\_prim\_rtest---perform primal ratio test} \subsubsection*{Synopsis} \begin{verbatim} int glp_prim_rtest(glp_prob *P, int len, const int ind[], const double val[], int dir, double eps); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_prim_rtest| performs the primal ratio test using an explicitly specified column of the simplex table. The current basic solution associated with the LP problem object must be primal feasible. The explicitly specified column of the simplex table shows how the basic variables $x_B$ depend on some non-basic variable $x$ (which is not necessarily presented in the problem object): $$ \begin{array}{l@{\ }c@{\ }r} (x_B)_1&=\dots+&\xi_{1}x\\ (x_B)_2&=\dots+&\xi_{2}x\\ \multicolumn{3}{c}{.\ \ .\ \ .\ \ .\ \ .\ \ .}\\ (x_B)_m&=\dots+&\xi_{m}x\\ \end{array} $$ The column is specifed on entry to the routine in sparse format. Ordinal numbers of basic variables $(x_B)_i$ should be placed in locations \verb|ind[1]|, \dots, \verb|ind[len]|, where ordinal number 1 to $m$ denote auxiliary variables, and ordinal numbers $m+1$ to $m+n$ denote structural variables. The corresponding non-zero coefficients $\xi_i$ should be placed in locations \verb|val[1]|, \dots, \verb|val[len]|. The arrays \verb|ind| and \verb|val| are not changed by the routine. The parameter \verb|dir| specifies direction in which the variable $x$ changes on entering the basis: $+1$ means increasing, $-1$ means decreasing. The parameter \verb|eps| is an absolute tolerance (small positive number, say, $10^{-9}$) used by the routine to skip $\xi_i$'s whose magnitude is less than \verb|eps|. The routine determines which basic variable (among those specified in \verb|ind[1]|, \dots, \verb|ind[len]|) reaches its (lower or upper) bound first before any other basic variables do, and which, therefore, should leave the basis in order to keep primal feasibility. \subsubsection*{Returns} The routine \verb|glp_prim_rtest| returns the index, \verb|piv|, in the arrays \verb|ind| and \verb|val| corresponding to the pivot element chosen, $1\leq$ \verb|piv| $\leq$ \verb|len|. If the adjacent basic solution is primal unbounded, and therefore the choice cannot be made, the routine returns zero. \subsubsection*{Comments} If the non-basic variable $x$ is presented in the LP problem object, the input column can be computed with the routine \verb|glp_eval_tab_col|; otherwise, it can be computed with the routine \verb|glp_transform_col|. \subsection{glp\_dual\_rtest---perform dual ratio test} \subsubsection*{Synopsis} \begin{verbatim} int glp_dual_rtest(glp_prob *P, int len, const int ind[], const double val[], int dir, double eps); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_dual_rtest| performs the dual ratio test using an explicitly specified row of the simplex table. The current basic solution associated with the LP problem object must be dual feasible. The explicitly specified row of the simplex table is a linear form that shows how some basic variable $x$ (which is not necessarily presented in the problem object) depends on non-basic variables $x_N$: $$x=\xi_1(x_N)_1+\xi_2(x_N)_2+\dots+\xi_n(x_N)_n.$$ The row is specified on entry to the routine in sparse format. Ordinal numbers of non-basic variables $(x_N)_j$ should be placed in locations \verb|ind[1]|, \dots, \verb|ind[len]|, where ordinal numbers 1 to $m$ denote auxiliary variables, and ordinal numbers $m+1$ to $m+n$ denote structural variables. The corresponding non-zero coefficients $\xi_j$ should be placed in locations \verb|val[1]|, \dots, \verb|val[len]|. The arrays \verb|ind| and \verb|val| are not changed by the routine. The parameter \verb|dir| specifies direction in which the variable $x$ changes on leaving the basis: $+1$ means that $x$ goes on its lower bound, so its reduced cost (dual variable) is increasing (minimization) or decreasing (maximization); $-1$ means that $x$ goes on its upper bound, so its reduced cost is decreasing (minimization) or increasing (maximization). The parameter \verb|eps| is an absolute tolerance (small positive number, say, $10^{-9}$) used by the routine to skip $\xi_j$'s whose magnitude is less than \verb|eps|. The routine determines which non-basic variable (among those specified in \verb|ind[1]|, \dots, \verb|ind[len]|) should enter the basis in order to keep dual feasibility, because its reduced cost reaches the (zero) bound first before this occurs for any other non-basic variables. \subsubsection*{Returns} The routine \verb|glp_dual_rtest| returns the index, \verb|piv|, in the arrays \verb|ind| and \verb|val| corresponding to the pivot element chosen, $1\leq$ \verb|piv| $\leq$ \verb|len|. If the adjacent basic solution is dual unbounded, and therefore the choice cannot be made, the routine returns zero. \subsubsection*{Comments} If the basic variable $x$ is presented in the LP problem object, the input row can be computed with the routine \verb|glp_eval_tab_row|; otherwise, it can be computed with the routine \verb|glp_transform_row|. %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%% \newpage \section{Post-optimal analysis routines} \subsection{glp\_analyze\_bound---analyze active bound of non-basic variable} \subsubsection*{Synopsis} \begin{verbatim} void glp_analyze_bound(glp_prob *P, int k, double *limit1, int *var1, double *limit2, int *var2); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_analyze_bound| analyzes the effect of varying the active bound of specified non-basic variable. The non-basic variable is specified by the parameter $k$, where $1\leq k\leq m$ means auxiliary variable of corresponding row, and $m+1\leq k\leq m+n$ means structural variable (column). Note that the current basic solution must be optimal, and the basis factorization must exist. Results of the analysis have the following meaning. \verb|value1| is the minimal value of the active bound, at which the basis still remains primal feasible and thus optimal. \verb|-DBL_MAX| means that the active bound has no lower limit. \verb|var1| is the ordinal number of an auxiliary (1 to $m$) or structural ($m+1$ to $m+n$) basic variable, which reaches its bound first and thereby limits further decreasing the active bound being analyzed. if \verb|value1| = \verb|-DBL_MAX|, \verb|var1| is set to 0. \verb|value2| is the maximal value of the active bound, at which the basis still remains primal feasible and thus optimal. \verb|+DBL_MAX| means that the active bound has no upper limit. \verb|var2| is the ordinal number of an auxiliary (1 to $m$) or structural ($m+1$ to $m+n$) basic variable, which reaches its bound first and thereby limits further increasing the active bound being analyzed. if \verb|value2| = \verb|+DBL_MAX|, \verb|var2| is set to 0. The parameters \verb|value1|, \verb|var1|, \verb|value2|, \verb|var2| can be specified as \verb|NULL|, in which case corresponding information is not stored. \newpage \subsection{glp\_analyze\_coef---analyze objective coefficient at basic variable} \subsubsection*{Synopsis} \begin{verbatim} void glp_analyze_coef(glp_prob *P, int k, double *coef1, int *var1, double *value1, double *coef2, int *var2, double *value2); \end{verbatim} \subsubsection*{Description} The routine \verb|glp_analyze_coef| analyzes the effect of varying the objective coefficient at specified basic variable. The basic variable is specified by the parameter $k$, where $1\leq k\leq m$ means auxiliary variable of corresponding row, and $m+1\leq k\leq m+n$ means structural variable (column). Note that the current basic solution must be optimal, and the basis factorization must exist. Results of the analysis have the following meaning. \verb|coef1| is the minimal value of the objective coefficient, at which the basis still remains dual feasible and thus optimal. \verb|-DBL_MAX| means that the objective coefficient has no lower limit. \verb|var1| is the ordinal number of an auxiliary (1 to $m$) or structural ($m+1$ to $m+n$) non-basic variable, whose reduced cost reaches its zero bound first and thereby limits further decreasing the objective coefficient being analyzed. If \verb|coef1| = \verb|-DBL_MAX|, \verb|var1| is set to 0. \verb|value1| is value of the basic variable being analyzed in an adjacent basis, which is defined as follows. Let the objective coefficient reaches its minimal value (\verb|coef1|) and continues decreasing. Then the reduced cost of the limiting non-basic variable (\verb|var1|) becomes dual infeasible and the current basis becomes non-optimal that forces the limiting non-basic variable to enter the basis replacing there some basic variable that leaves the basis to keep primal feasibility. Should note that on determining the adjacent basis current bounds of the basic variable being analyzed are ignored as if it were free (unbounded) variable, so it cannot leave the basis. It may happen that no dual feasible adjacent basis exists, in which case \verb|value1| is set to \verb|-DBL_MAX| or \verb|+DBL_MAX|. \verb|coef2| is the maximal value of the objective coefficient, at which the basis still remains dual feasible and thus optimal. \verb|+DBL_MAX| means that the objective coefficient has no upper limit. \verb|var2| is the ordinal number of an auxiliary (1 to $m$) or structural ($m+1$ to $m+n$) non-basic variable, whose reduced cost reaches its zero bound first and thereby limits further increasing the objective coefficient being analyzed. If \verb|coef2| = \verb|+DBL_MAX|, \verb|var2| is set to 0. \verb|value2| is value of the basic variable being analyzed in an adjacent basis, which is defined exactly in the same way as \verb|value1| above with exception that now the objective coefficient is increasing. The parameters \verb|coef1|, \verb|var1|, \verb|value1|, \verb|coef2|, \verb|var2|, \verb|value2| can be specified as \verb|NULL|, in which case corresponding information is not stored. %* eof *%