src/work/alpar/named-param-test.cc
author ladanyi
Tue, 05 Apr 2005 22:37:19 +0000
changeset 1308 0274efa2222f
permissions -rw-r--r--
Applied the changes which somehow vanished during my last merge. Thanks goes
to Marci for noticing this. In detail:
- added amsmath and amssymb latex packages for latex documentation
- src/demo is also scanned for doxygen input files
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// -*- mode:C++ -*-
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//////////////////////////////////////////////////////////////////////
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// Named "function" parameters
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//////////////////////////////////////////////////////////////////////
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class named_fn 
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{
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  int _id;
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  double _val;
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  int _dim;
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  public:
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  named_fn() : _id(0), _val(1), _dim(2) {}
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  named_fn& id(int p)     { _id  = p ; return *this; }
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  named_fn& val(double p) { _val = p ; return *this; }
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  named_fn& dim(int p)    { _dim = p ; return *this; }
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  ~named_fn() {
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    //Itt van maga az algoritmus
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  }
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};
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//Hasznalat:
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//named_fn().id(3);
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//named_fn().id(3).val(2);
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//named_fn().dim(4).id(3);
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//////////////////////////////////////////////////////////////////////
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// Named class template parameters (A)
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//////////////////////////////////////////////////////////////////////
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template<class A=int,class B=double>
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class Named_T
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{
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public:
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  typedef A Atype;
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  typedef B Btype;
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  template <class T> class SetAType : public Named_T<T,Btype> { };
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  template <class T> class SetBType : public Named_T<Atype,T> { };
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};
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// Named_T<>::SetAType<double>::SetBType<double>
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//////////////////////////////////////////////////////////////////////
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// Named class template parameters (A)
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//////////////////////////////////////////////////////////////////////
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struct _NTR 
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{
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  typedef int Atype;
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  typedef double Btype;
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};
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template<class TR=_NTR>
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class Named_TR
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{
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public:
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  typedef typename TR::Atype Atype;
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  typedef typename TR::Btype Btype;
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  Atype a;
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  Btype b;
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  template <class T>
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  struct ATR : public TR {
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    typedef T Atype;
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  };
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  template <class T>
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  class SetAType : public Named_TR<ATR<T> > { };
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  template <class T>
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  struct BTR : public TR {
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    typedef T Btype;
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  };
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  template <class T>
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  class SetBType : public Named_TR<BTR<T> > { };
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  Named_TR() {};
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  Named_TR<TR> &setA(Atype _a) { a=_a; return *this;}
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  Named_TR<TR> &setB(Btype _b) { b=_b; return *this;}
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  void run() {
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    // itt az algoritmus
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  }
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  //////////////////////////////////////////////////////////////////////
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  template<class T>
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  SetAType<T> SETA(T t) { SetAType<T> r; r.a=t; r.b=b; return r;}
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  template<class T>
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  SetBType<T> SETB(T t) { SetBType<T> r; r.a=a; r.b=t; return r;}
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};
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// Hasznalat:
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// 1.
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//   Named_TR<>::SetAType<double> nt;
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//   Named_TR<>::SetBType<double>::SetAType<double> nt2;
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//   nt2.setA(5).setB(6).run();
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// 2.
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//   double x;
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//   Named_TR<>().SETA(5.2).SETB(x).run();
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// 3. 
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//   struct MyTr : public _NTR { typedef float Btype; };
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//   int main() 
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//   {
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//     Named_TR<MyTr> d2; d2=d2;
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//   }
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// Sajnos ezt csak a fuggvenyen kivul lehet deklaralni:
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struct MyTr : public _NTR { typedef float Btype; };
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typedef Named_T<> Named_TN;
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int main()
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{
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  Named_T<> a;a=a;
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  Named_T<>::SetAType<double> b;b=b;
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  Named_T<>::SetAType<double>::SetBType<int> c;c=c;
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  Named_TR<> a2;a2=a2;
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  Named_TR<>::SetAType<double> b2;b2=b2;
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  Named_TR<>::SetAType<double>::SetBType<int> c2;c2=c2;
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  //De igy is lehet:
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  Named_TR<MyTr> d2; d2=d2;
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  named_fn().id(3);
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  named_fn().id(3).val(2);
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  named_fn().dim(4).id(3);
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   Named_TR<>::SetAType<double> nt;
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   Named_TR<>::SetBType<double>::SetAType<double> nt2;
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   nt2.setA(5).setB(6).run();
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   double x;
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   Named_TR<>().SETA(5.2).SETB(x).run();
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}
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