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// -*- c++ -*-
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#include <iostream>
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#include <fstream>
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#include <lemon/time_measure.h>
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#include <lp_solver_base.h>
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using std::cout;
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using std::endl;
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using namespace lemon;
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/*
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for n=3,4 , the program is very fast
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for n=5, with glpk, the run takes hours
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*/
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int main(int, char **) {
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const int n=4;
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const double row_sum=(1.0+n*n)*n/2;
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Timer ts;
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ts.reset();
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typedef LPGLPK LPSolver;
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typedef LPSolver::Col Col;
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LPSolver lp;
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typedef std::map<std::pair<int, int>, Col> Coords;
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Coords x;
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// we create a new variable for each entry
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// of the magic square
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for (int i=1; i<=n; ++i) {
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for (int j=1; j<=n; ++j) {
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Col col=lp.addCol();
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x[std::make_pair(i,j)]=col;
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lp.setColLowerBound(col, 1.0);
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lp.setColUpperBound(col, double(n*n));
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}
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}
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LPSolver::Expression expr3, expr4;
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for (int i=1; i<=n; ++i) {
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LPSolver::Expression expr1, expr2;
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for (int j=1; j<=n; ++j) {
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expr1+=x[std::make_pair(i, j)];
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expr2+=x[std::make_pair(j, i)];
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}
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// sum of rows and columns
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lp.addRow(expr1==row_sum);
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lp.addRow(expr2==row_sum);
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expr3+=x[std::make_pair(i, i)];
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expr4+=x[std::make_pair(i, (n+1)-i)];
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}
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// sum of the diagonal entries
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lp.addRow(expr3==row_sum);
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lp.addRow(expr4==row_sum);
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lp.solveSimplex();
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cout << "elapsed time: " << ts << endl;
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for (int i=1; i<=n; ++i) {
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for (int j=1; j<=n; ++j) {
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cout << "x("<<i<<","<<j<<")="<<lp.getPrimal(x[std::make_pair(i,j)])
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<< endl;
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}
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}
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// we make new binary variables for each pair of
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// entries of the square to achieve that
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// the values of different entries are different
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lp.setMIP();
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for (Coords::const_iterator it=x.begin(); it!=x.end(); ++it) {
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Coords::const_iterator jt=it; ++jt;
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for(; jt!=x.end(); ++jt) {
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Col col1=(*it).second;
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Col col2=(*jt).second;
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Col col=lp.addCol();
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lp.setColLowerBound(col, 0.0);
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lp.setColUpperBound(col, 1.0);
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lp.addRow(double(-n*n+1.0)<=1.0*col2-1.0*col1-double(n*n)*col<=-1.0);
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lp.setColInt(col);
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}
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}
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cout << "elapsed time: " << ts << endl;
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lp.solveSimplex();
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// let's solve the integer problem
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lp.solveBandB();
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cout << "elapsed time: " << ts << endl;
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for (int i=1; i<=n; ++i) {
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for (int j=1; j<=n; ++j) {
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cout << "x("<<i<<","<<j<<")="<<lp.getMIPPrimal(x[std::make_pair(i,j)])
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<< endl;
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}
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}
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}
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