r942:754272f20318
Sun, 28 Feb 2010 19:58:24
[Not Reviewed]
0 comments (0 inline)
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| ... | ... |
@@ -91,7 +91,7 @@ |
| 91 | 91 |
if(report) std::cerr << "\nMax flow value: " << pre.flowValue() << '\n'; |
| 92 | 92 |
} |
| 93 | 93 |
|
| 94 |
template<class Value> |
|
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template<class Value, class LargeValue> |
|
| 95 | 95 |
void solve_min(ArgParser &ap, std::istream &is, std::ostream &, |
| 96 | 96 |
Value infty, DimacsDescriptor &desc) |
| 97 | 97 |
{
|
| ... | ... |
@@ -127,7 +127,8 @@ |
| 127 | 127 |
if (report) {
|
| 128 | 128 |
std::cerr << "Run NetworkSimplex: " << ti << "\n\n"; |
| 129 | 129 |
std::cerr << "Feasible flow: " << (res ? "found" : "not found") << '\n'; |
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if (res) std::cerr << "Min flow cost: " |
|
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if (res) std::cerr << "Min flow cost: " |
|
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<< ns.template totalCost<LargeValue>() << '\n'; |
|
| 131 | 132 |
} |
| 132 | 133 |
} |
| 133 | 134 |
|
| ... | ... |
@@ -151,7 +152,7 @@ |
| 151 | 152 |
} |
| 152 | 153 |
|
| 153 | 154 |
|
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template<class Value> |
|
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template<class Value, class LargeValue> |
|
| 155 | 156 |
void solve(ArgParser &ap, std::istream &is, std::ostream &os, |
| 156 | 157 |
DimacsDescriptor &desc) |
| 157 | 158 |
{
|
| ... | ... |
@@ -169,7 +170,7 @@ |
| 169 | 170 |
switch(desc.type) |
| 170 | 171 |
{
|
| 171 | 172 |
case DimacsDescriptor::MIN: |
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solve_min<Value>(ap,is,os,infty,desc); |
|
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solve_min<Value, LargeValue>(ap,is,os,infty,desc); |
|
| 173 | 174 |
break; |
| 174 | 175 |
case DimacsDescriptor::MAX: |
| 175 | 176 |
solve_max<Value>(ap,is,os,infty,desc); |
| ... | ... |
@@ -264,14 +265,16 @@ |
| 264 | 265 |
} |
| 265 | 266 |
|
| 266 | 267 |
if(ap.given("double"))
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solve<double>(ap,is,os,desc); |
|
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solve<double, double>(ap,is,os,desc); |
|
| 268 | 269 |
else if(ap.given("ldouble"))
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solve<long double>(ap,is,os,desc); |
|
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solve<long double, long double>(ap,is,os,desc); |
|
| 270 | 271 |
#ifdef LEMON_HAVE_LONG_LONG |
| 271 | 272 |
else if(ap.given("long"))
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solve<long long>(ap,is,os,desc); |
|
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solve<long long, long long>(ap,is,os,desc); |
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else solve<int, long long>(ap,is,os,desc); |
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#else |
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else solve<int, long>(ap,is,os,desc); |
|
| 273 | 277 |
#endif |
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else solve<int>(ap,is,os,desc); |
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| 275 | 278 |
|
| 276 | 279 |
return 0; |
| 277 | 280 |
} |
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