1 | // -*- c++ -*- |
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2 | /** |
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3 | 2 dimensional vector (plainvector) implementation |
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4 | |
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5 | */ |
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6 | #ifndef HUGO_XY_H |
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7 | #define HUGO_XY_H |
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8 | |
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9 | #include <iostream> |
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10 | |
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11 | namespace hugo { |
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12 | |
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13 | template<typename T> |
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14 | class xy { |
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15 | T _x,_y; |
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16 | |
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17 | public: |
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18 | |
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19 | ///Default constructor: both coordinates become 0 |
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20 | xy() { _x=_y=0; } |
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21 | |
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22 | ///Constructing from coordinates |
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23 | xy(T a, T b) { _x=a; _y=b; } |
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24 | |
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25 | ///Gives back the x coordinate |
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26 | T x(){ |
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27 | return _x; |
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28 | }; |
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29 | |
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30 | ///Gives back the y coordinate |
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31 | T y(){ |
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32 | return _y; |
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33 | }; |
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34 | |
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35 | ///Gives back the square of the norm of the vector |
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36 | T normSquare(){ |
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37 | return _x*_x+_y*_y; |
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38 | }; |
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39 | |
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40 | ///Increments the left hand side by u |
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41 | xy<T>& operator +=(const xy<T>& u){ |
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42 | _x += u._x; |
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43 | _y += u._y; |
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44 | return *this; |
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45 | }; |
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46 | |
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47 | ///Decrements the left hand side by u |
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48 | xy<T>& operator -=(const xy<T>& u){ |
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49 | _x -= u._x; |
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50 | _y -= u._y; |
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51 | return *this; |
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52 | }; |
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53 | |
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54 | ///Multiplying the left hand side with a scalar |
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55 | xy<T>& operator *=(const T &u){ |
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56 | _x *= u; |
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57 | _y *= u; |
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58 | return *this; |
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59 | }; |
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60 | |
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61 | ///Dividing the left hand side by a scalar |
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62 | xy<T>& operator /=(const T &u){ |
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63 | _x /= u; |
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64 | _y /= u; |
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65 | return *this; |
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66 | }; |
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67 | |
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68 | ///Returns the scalar product of two vectors |
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69 | T operator *(const xy<T>& u){ |
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70 | return _x*u._x+_y*u._y; |
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71 | }; |
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72 | |
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73 | ///Returns the sum of two vectors |
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74 | xy<T> operator+(const xy<T> &u) const { |
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75 | xy<T> b=*this; |
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76 | return b+=u; |
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77 | }; |
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78 | |
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79 | ///Returns the difference of two vectors |
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80 | xy<T> operator-(const xy<T> &u) const { |
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81 | xy<T> b=*this; |
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82 | return b-=u; |
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83 | }; |
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84 | |
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85 | ///Returns a vector multiplied by a scalar |
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86 | xy<T> operator*(const T &u) const { |
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87 | xy<T> b=*this; |
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88 | return b*=u; |
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89 | }; |
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90 | |
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91 | ///Returns a vector divided by a scalar |
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92 | xy<T> operator/(const T &u) const { |
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93 | xy<T> b=*this; |
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94 | return b/=u; |
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95 | }; |
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96 | |
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97 | ///Testing equality |
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98 | bool operator==(const xy<T> &u){ |
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99 | return (_x==u._x) && (_y==u._y); |
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100 | }; |
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101 | |
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102 | ///Testing inequality |
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103 | bool operator!=(xy u){ |
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104 | return (_x!=u._x) || (_y!=u._y); |
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105 | }; |
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106 | |
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107 | }; |
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108 | |
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109 | ///Reading a plainvector from a stream |
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110 | template<typename T> |
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111 | inline |
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112 | std::istream& operator>>(std::istream &is, xy<T> &z) |
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113 | { |
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114 | ///This is not the best solution here: I didn't know how to solve this with friend functions |
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115 | T a,b; |
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116 | is >> a >> b; |
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117 | xy<T> buf(a,b); |
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118 | z=buf; |
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119 | return is; |
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120 | } |
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121 | |
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122 | ///Outputting a plainvector to a stream |
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123 | template<typename T> |
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124 | inline |
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125 | std::ostream& operator<<(std::ostream &os, xy<T> z) |
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126 | { |
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127 | os << "(" << z.x() << ", " << z.y() << ")"; |
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128 | return os; |
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129 | } |
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130 | |
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131 | } //namespace hugo |
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132 | |
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133 | #endif //HUGO_XY_H |
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