This read-only map returns the logical 'and' of the values of the two given maps. Its Key
type is inherited from M1
and its Value
type is bool
. M2::Key
must be convertible to M1::Key
.
If m1
is of type M1
and m2
is of M2
, then for
am[x]
will be equal to m1[x]&&m2[x]
.
The simplest way of using this map is through the andMap() function.
#include <lemon/maps.h>
Public Types | |
typedef M1::Key | Key |
| |
typedef bool | Value |
| |
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typedef M1::Key | Key |
The key type of the map. | |
typedef bool | Value |
The value type of the map. (The type of objects associated with the keys). | |
Public Member Functions | |
AndMap (const M1 &m1, const M2 &m2) | |
Constructor. | |
Value | operator[] (const Key &k) const |
| |
Related Functions | |
(Note that these are not member functions.) | |
template<typename M1 , typename M2 > | |
AndMap< M1, M2 > | andMap (const M1 &m1, const M2 &m2) |
Returns an AndMap class. | |